local mlg = math.log
local p, q = io.read("*n", "*n")
local lg2 = mlg(2)
local function solve(x)
  return x * x < p + q * x * mlg(x) / lg2
end

local min, max = 1, 1000000007 * 1000000007
for irep = 1, 2000 do
  local mid = (min + max) / 2
  if solve(mid) then
    min = mid
  else
    max = mid
  end
end
print(string.format("%.10f", min))