#include<iostream>
#include<string>
#include<cstdio>
#include<vector>
#include<cmath>
#include<algorithm>
#include<functional>
#include<iomanip>
#include<queue>
#include<ciso646>
#include<random>
#include<map>
#include<set>
#include<complex>
#include<bitset>
#include<stack>
#include<unordered_map>
#include<utility>
#include<tuple>
using namespace std;
typedef long long ll;
typedef unsigned int ui;
const ll mod = 1700000007;
const ll INF = (ll)1000000007 * 1000000007;
typedef pair<int, int> P;
#define stop char nyaa;cin>>nyaa;
#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define Per(i,sta,n) for(int i=n-1;i>=sta;i--)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
typedef long double ld;
const ld eps = 1e-8;
const ld pi = acos(-1.0);
typedef pair<ll, ll> LP;
typedef pair<P,P> PP;
int dx[4]={1,-1,0,0};
int dy[4]={0,0,1,-1};

int n;
set<int> se;
map<int,int> zaatu;
vector<PP> items;
int dp[2][(1 << 16)][50];

void solve(){
  cin >> n;
  rep(i,n){
    int a,b,c;cin >> a >> b >> c;vector<int> p={a,b,c};sort(p.begin(),p.end());
    se.insert(a);se.insert(b);se.insert(c);
    items.emplace_back(P(p[0],p[1]),P(p[2],i));
    items.emplace_back(P(p[0],p[2]),P(p[1],i));
    items.emplace_back(P(p[1],p[2]),P(p[0],i));
  }
  int max_l=0;auto idx=se.begin();
  while(idx!=se.end()){
    zaatu[*idx]=max_l;
    idx++;
    max_l+=1;
  }
  sort(items.begin(),items.end());
  int N=(1 << n);
  rep(i,3*n){
    int d=zaatu[items[i].first.second],h=items[i].second.first,id=items[i].second.second;
    //cout << d << " " << h << " " << id << endl;
    rep(S,N){
      rep(j,max_l){
        dp[(i+1)%2][S][j]=max(dp[(i+1)%2][S][j],dp[i%2][S][j]);
        if(S & (1 << id)) continue;
        //cout << j << " " << d << " " << h << endl;
        if(j<=d){
          dp[(i+1)%2][S|(1 << id)][d]=max(dp[(i+1)%2][S|(1 << id)][d],dp[i%2][S][j]+h);
          //cout << i+1 << " " << (S|(1 << id)) << " " << d << " " << dp[i+1][S|(1 << id)][d] << endl;
        }
      }
    }
  }
  int ans=0;
  rep(S,N){
    rep(j,max_l){
      //cout << bitset<2>(S) <<  " " << j << " " << dp[3*n][S][j] << endl;
      ans=max(ans,dp[(3*n)%2][S][j]);
    }
  }
  cout << ans << endl;
}

int main(){
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout << fixed << setprecision(50);
    solve();
}