import sys

read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines

MOD = 10**9 + 7

A, B, P = readline().split()

P = int(P)

A = [0, 0, 0, 0, 0] + [int(x) - ord('0') for x in A]
B = [0, 0, 0, 0, 0] + [int(x) - ord('0') for x in B]

def solve(A, P, include=True):
    total = 0
    no_3 = 0
    cnt = (0, 1, 2, 3, 3, 4, 5, 6, 7, 8)
    full_use_3 = False
    MOD3 = 3 * MOD
    for x in A[:-6]:
        total = (10 * total + x) % MOD3
        no_3 = (9 * no_3) % MOD
        if not full_use_3:
            no_3 += cnt[x]
        full_use_3 |= x == 3
    n = no_3 * 3
    no_3 = [n, n, n]
    x = A[-6]
    full_use_3 |= 3 in A[:-6]
    for d in range(x):
        if full_use_3 or d == 3:
            continue
        no_3[(total + d) % 3] += 1
    total = (total * 10 + x) % MOD3
    use_3 = (total - sum(no_3)) % MOD
    full_mod_3 = total % 3

    U = 0
    for x in A[-5:]:
        U = 10 * U + x

    ret = 0
    for x in range(10**5):
        if x % P == 0:
            continue
        if '3' in str(x):
            ret += total
        else:
            ret += use_3 + no_3[(-x) % 3]

    for x in range(U + include):
        if x % P == 0:
            continue
        if '3' in str(x) or full_use_3:
            ret += 1
        else:
            ret += (full_mod_3 + x) % 3 == 0
    return ret

def solve_naive(A, P, include):
    N = 0
    for x in A:
        N = 10 * N + x
    ret = 0
    for x in range(N + include):
        if x % P == 0:
            continue
        ret += '3' in str(x) or x % 3 == 0
    return ret

x = solve(B, P, True) - solve(A, P, False)
print(x % MOD)