#include<bits/stdc++.h>
using namespace std;
#define fs first
#define sc second
#define pb push_back
#define mp make_pair
#define eb emplace_back
#define ALL(A) A.begin(),A.end()
#define RALL(A) A.rbegin(),A.rend()
typedef long long LL;
typedef pair<LL,LL> P;
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }
template<typename T> T gcd(T a,T b){return b?gcd(b,a%b):a;}
const LL mod=1000000007;
const LL LINF=1LL<<62;
const int INF=1<<30;
int dx[]={1,0,-1,0,1,-1,1,-1};
int dy[]={0,1,0,-1,1,-1,-1,1};


typedef vector<vector<LL>> mat;

mat mul(mat A,mat B){
    mat C(A.size(),vector<LL> (B[0].size()));
    for(int i=0;i<A.size();i++){
        for(int k=0;k<B.size();k++){
            for(int j=0;j<B[0].size();j++){
                C[i][j]=(C[i][j]+A[i][k]*B[k][j])%mod;
            }
        }
    }
    return C;
}

mat pow(mat A,LL n){
    mat B(A.size(),vector<LL> (A.size()));
    for(int i=0;i<A.size();i++){
        B[i][i]=1;
    }
    while(n>0){
        if(n&1) B=mul(B,A);
        A=mul(A,A);
        n>>=1;
    }
    return B;
}



int main(){
    int p,k;cin >> p >> k;
    mat A(2,vector<LL> (2,0));
    mat h(2,vector<LL> (1,0));
    h[0][0] = 1;
    A[0][0] = p + 1;
    A[0][1] = 2 * (p - 1);
    A[1][0] = 1;
    A[1][1] = 2 * (p - 1);
    auto Ak = pow(A, k);
    auto ans = mul(Ak, h);
    cout << ans[0][0] << endl;
    return 0;
}