#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #define rep(x, to) for (int x = 0; x < (to); x++) #define REP(x, a, to) for (int x = (a); x < (to); x++) #define foreach(itr, x) for (typeof((x).begin()) itr = (x).begin(); itr != (x).end(); itr++) #define EPS (1e-14) using namespace std; typedef long long ll; typedef pair PII; typedef pair PLL; typedef complex Complex; typedef vector< vector > Mat; ll N; ll ans = 1; vector prime_factorization(ll x) { vector res; for (ll i = 2; i * i <= x; i++) { if (x % i != 0) continue; PLL cur = PLL(0, 0); cur.first = i; while (x % i == 0) { cur.second++; x /= i; } res.push_back(cur); } // xが素数であった場合はxを追加 if (x != 1) { res.push_back(PLL(x, 1)); } return res; } void solve(ll x) { vector factor = prime_factorization(x); #if 0 rep(i, factor.size()) { cout << factor[i].first << " " << factor[i].second << endl; } #endif for (int i = 0; i < factor.size() && factor[i].first != x; i++) { ll p = factor[i].first; ll size = factor[i].second; ll tmp = p; rep(j, size) { tmp *= p; } ans *= (tmp - 1) / (p - 1); } // 最後の素数が自身(x)であった場合 if (factor.size() > 0 && factor.back().first == x) { ans *= (1 + factor.back().first); } cout << ans << endl; } int main() { cin >> N; solve(N % 2 == 0 ? N / 2 : N); return 0; }