#include #define rep(i,n) for(int i=(0);i<(n);i++) using namespace std; typedef long long ll; typedef pair pii; int n; vector a, b, d; bool cond(int k){ if(k == 0) return true; bool dp[k+1][k+1]; rep(i, k + 1) rep(j, k + 1) dp[i][j] = false; dp[0][0] = true; rep(i, k) { dp[i+1][0] = dp[i][0] && (d[k-i-1] <= a[i+1] + b[0]); rep(j, i) dp[i+1][j+1] = (dp[i][j] || dp[i][j+1]) && (d[k-i-1] <= a[i-j] + b[j+1]); dp[i+1][i+1] = dp[i][i] && (d[k-i-1] <= a[0] + b[i+1]); } rep(i, k + 1) if(dp[k][i]) return true; return false; } // condを満たす最大のxを求める(upper_bound) // 全てのxが条件を満たさない場合は-1を返す(-1はとりえない値) int upper_bound_cond(){ int lb = -1, ub = n+1; while(ub - lb > 1){ int mid = (lb + ub) / 2; bool ok = cond(mid); // cout << mid << "," << ok << "\n"; if(ok) lb = mid; // Answer is in [mid, ub) else ub = mid; // Answer is in [lb, mid) } // now lb + 1 = ub return lb; } int main(){ cin.tie(0); ios::sync_with_stdio(false); cin >> n; a.resize(n + 1); b.resize(n + 1); d.resize(n); rep(i, n + 1) cin >> a[i]; rep(i, n + 1) cin >> b[i]; rep(i, n) cin >> d[i]; sort(d.begin(), d.end()); cout << upper_bound_cond() << endl; }