#include using namespace std; using ll = long long; int main() { int n, k; cin >> n >> k; if(n & 1) { //int front = min((k % 2 == 1 ? n / 2 : (n + 1) / 2), ); int front = (k + 2) / 2; int back = (k + 1) / 2; //int back = min((k % 2 == 1 ? (n + 1) / 2 : n / 2), (k % 2 ? k : k - 1)); cout << min(n, front + back) << endl; } else { int front = (k + 2) / 2; int back = (k + 1) / 2; cout << min(n / 2, front + back) << endl; } }