#include using namespace std; using ll = long long; using ld = long double; using vl = vector; template using vc = vector; template using vvc = vector>; #define eb emplace_back #define all(x) (x).begin(), (x).end() #define rep(i, n) for (ll i = 0; i < (n); i++) #define repr(i, n) for (ll i = (n)-1; i >= 0; i--) #define repe(i, l, r) for (ll i = (l); i < (r); i++) #define reper(i, l, r) for (ll i = (r)-1; i >= (l); i--) #define repa(i,n) for (auto& i: n) template inline bool chmax(T &a, const T &b) { if (a inline bool chmin(T &a, const T &b) { if (b void verr(const T& a, const N& n) { rep(i, n) cerr << a[i] << " "; cerr << "\n" << flush; } ll dbgt = 1; void err() { cerr << "passed " << dbgt++ << "\n" << flush; } template void err(H&& h,T&&... t){ cerr<< h << (sizeof...(t)?" ":"\n") << flush; if(sizeof...(t)>0) err(forward(t)...); } #endif const ll INF = 5e18; const ld EPS = 1e-11; const ld PI = acos(-1.0L); const ll MOD = 1e9 + 7; // const ll MOD = 998244353; //--------------------------------------------------------------------------------// // 1~1e5までの値について素数:自身の値, 合成数:最小の素因数 の配列を返す constexpr int PSIZE = 2e5 + 1; struct eratosthenes_sieve{ int Primes[PSIZE]; bool isPrime[PSIZE]; constexpr eratosthenes_sieve(): Primes(), isPrime(){ iota(Primes, Primes + PSIZE, 0); fill(isPrime, isPrime + PSIZE, 0); for (int i = 2; i < PSIZE; i++){ if (Primes[i] != i) continue; for (int s = i * 2; s < PSIZE; s += i){ Primes[s] = i; } isPrime[i] = true; } } // 数値vの素因数の配列を昇順で取得 vector get_pfactor(int v){ vector res; int p = Primes[v]; while(v > 1){ while (Primes[v] == p) v /= Primes[v]; res.emplace_back(p); p = Primes[v]; } reverse(res.begin(), res.end()); return res; } // 数値vの素因数分解を取得 map get_factrization(int v){ map mp; while(v>1){ mp[Primes[v]]++; v /= Primes[v]; } return mp; } }; using ES = struct eratosthenes_sieve; int main() { init(); ll N; cin >> N; ES es; if(N==1){ cout << 1 << endl; return 0; } N -= 2; ll pi = 0; vl cand; rep(i,PSIZE){ if (es.Primes[i] <= 100000) continue; pi++; cand.eb(es.Primes[i]); if(pi==10){ break; } } vl ans; rep(i,10)repe(j,i,10){ ans.eb(cand[i] * cand[j]); } sort(all(ans)); cout << ans[N] << endl; }