#include #define rep(i,n) for (int i = 0; i < (n); i ++) using namespace std; typedef long long ll; typedef pair PL; typedef pair P; const int INF = 1e9; const ll MOD = 1e9 + 7; struct UnionFind { int N; vector parents; UnionFind(int _N) : N(_N){ parents = vector(N,-1); } int find(int x) { //xの親を返す if (parents[x] < 0) return x; return parents[x] = find(parents[x]); } void unite(int x, int y) { //xとyの含むグループを併合 int px = find(x); int py = find(y); if (parents[px] > parents[py]) swap(px,py); if (px != py) { parents[px] += parents[py]; parents[py] = px; } } bool same(int x, int y) { //x,yが同じグループにいるか判定 return find(x) == find(y); } int size(int x) { //xと同じグループのメンバーの個数 return -parents[find(x)]; } vector root() {//ufの根を列挙 vector res; for (int i = 0; i < N; i ++) { if (parents[i] < 0) res.push_back(i); } return res; } int group_count() { //ufのグループの数を数える int cnt = 0; for (int i = 0; i < N; i ++) { if (parents[i] < 0) cnt ++; } return cnt; } }; int main() { int L,R; cin >> L >> R; UnionFind uf(R - L + 1); for (int i = L;i < R + 1;i++){ for (int j = 1;j*i < R + 1;j++){ uf.unite(i - L,j*i - L); } } cout << uf.group_count() - 1 << endl; }