#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #define _overload3(_1,_2,_3,name,...) name #define _rep(i,n) repi(i,0,n) #define repi(i,a,b) for(ll i=ll(a);ibool chmax(T &a, const T &b) { if (abool chmin(T &a, const T &b) { if (b void cins(itr first,itr last){ for (auto i = first;i != last;i++){ cin >> (*i); } } template void array_output(itr start,itr goal){ string ans = "",k = " "; for (auto i = start;i != goal;i++) ans += to_string(*i)+k; if (!ans.empty()) ans.pop_back(); PRINT(ans); } ll gcd(ll a, ll b) { return a ? gcd(b%a,a) : b; } const ll INF = 1e18; const ll MOD = 1000000007; const ll MOD2 = 998244353; typedef pair P; typedef pair point; const ll MAX = 200000; constexpr ll nx[8] = {1,0,-1,0,1,-1,1,-1}; constexpr ll ny[8] = {0,1,0,-1,1,1,-1,-1}; int main(){ cin.tie(0); ios::sync_with_stdio(false); ll n,q; cin >> n >> q; vector a(n); cins(all(a)); vector> dp(n+1,vector(n+1,0)); dp[0][0] = 1; rep(i,n){ (dp[i+1][0] = dp[i][0]*(a[i]-1))%=MOD2; rep(j,1,n+1){ (dp[i+1][j] = dp[i][j]*(a[i]-1)+dp[i][j-1])%=MOD2; } } ll b; rep(i,q){ cin >> b; PRINT(dp[n][b]); } }