#include <bits/stdc++.h>
#include <unistd.h>
#include <sys/time.h>
#include <stdlib.h>
 
using namespace std;
 
typedef long long ll;
typedef pair<ll,ll> P;
typedef pair<P, ll> T;
typedef pair<long double , ll> Ps;
 
long long int INF = 2e18;
const ll fact_table = 3200008;
double Pi = 3.1415926535897932384626;

priority_queue <ll> pql;
priority_queue <P> pqp;
priority_queue <P> bag;
//big priority queue
priority_queue <ll,vector<ll>,greater<ll> > pqls;
priority_queue <P,vector<P>,greater<P> > pqps;
//small priority queue
//top pop
 
ll dx[8]={1,0,-1,0,1,1,-1,-1};
ll dy[8]={0,1,0,-1,1,-1,-1,1};
char dir[] = "DRUL";
//↓,→,↑,←

#define endl "\n"
#ifdef ENJAPMA
    #undef endl
#endif
#define p(x) cout<<x<<endl;
#define el cout<<endl;
#define pe(x) cout<<x<<" ";
#define ps(x) cout<<fixed<<setprecision(25)<<x<<endl;
#define pu(x) cout<<(x);
#define pb push_back
#define lb lower_bound
#define ub upper_bound
#define CLEAR(a) a = decltype(a)(); 
#define pc(x) cout << x << ",";
 
const ll mod = 998244353ll;
// const ll mod = 1000000007ll;
  
ll mypow(ll number1,ll number2, ll mod){
    if(number2 == 0){
        return 1ll;
    }else{
        ll number3 = mypow(number1,number2 / 2, mod);
        number3 *= number3;
        number3 %= mod;
        if(number2%2==1){
            number3 *= number1;
            number3 %= mod;
        }
        return number3;
    }
}
void YES(bool condition){
    if(condition){
        p("YES");
    }else{
        p("NO");
    }
    return;
}
void Yes(bool condition){
    if(condition){
        p("Yes");
    }else{
        p("No");
    }
    return;
}

namespace NTT {
  void DFT(const ll m, const ll root, vector<ll> &a, bool rev = false) {
    ll N = a.size(), h = 0;
 
    for (ll i = 0; 1 << i < N; i++) h++;
    for (ll i = 0; i < N; i++) {
      ll j = 0;
      for (ll k = 0; k < h; k++)
        j |= (i >> k & 1) << (h - 1 - k);
      if (i < j) swap(a[i], a[j]);
    }
 
    for (ll i = 1; i < N; i *= 2) {
      ll base = mypow(root, (m - 1) / i / 2, m);
      if (rev) base = mypow(base, m - 2, m);
      ll w = 1;
      for (ll j = 0; j < i; j++) {
        for (ll k = 0; k < N; k += i*2) {
          ll s = a[j+k], t = a[j+k+i] * w % m;
          a[j+k+0] = (s + t) % m;
          a[j+k+i] = (s - t + m) % m;
        }
        w = w * base % m;
      }
    }
 
    if (rev) {
      ll tmp = mypow(N, m-2, m);
      for(ll &v : a) v = v * tmp % m;
    }
  }
 
  //(1012924417, 5), (924844033, 5)
 
  vector<ll> conv(const ll _mod, const ll root, const vector<ll> &a, const vector<ll> &b) {
    ll s = 1, t = a.size() + b.size() - 1;
    while(s < t) s *= 2;
 
    vector<ll> F(s), G(s);
    for(ll i = 0; i < (ll)a.size(); i++) F[i] = a[i];
    for(ll i = 0; i < (ll)b.size(); i++) G[i] = b[i];
    DFT(_mod, root, F); DFT(_mod, root, G);
 
    for(ll i = 0; i < s; i++) F[i] = (ll)F[i] * G[i] % _mod;
    DFT(_mod, root, F, true);
    // pe(F.size());p(t);
    F.resize(t);
    return F;
  }
};

// auto res = NTT::conv(mod, 3ll, atable, btable);

/*
ll fact[fact_table + 5],rfact[fact_table + 5]; 
 
void c3_init(){
    fact[0] = rfact[0] = 1;
    for(ll i=1; i<=fact_table; i++){
        fact[i] = (fact[i-1]*i) % mod;
    }
    rfact[fact_table] = mypow(fact[fact_table],mod - 2, mod);
    for(ll i=fact_table; i>=1; i--){
       rfact[i-1] = rfact[i] * i;
       rfact[i-1] %= mod;
    }
    return;}
ll c3(ll n,ll r){
    return (((fact[n] * rfact[r]) % mod ) * rfact[n-r]) % mod;}
*/

bool multicase = false;

ll n,m,num,a,b,c,d,e,h,q;
ll w, k, ans;
ll x[500005], y[500005];

deque<vector<ll>> G;
vector<ll> v;

void solve(){
    cin >> n >> q;
    for(ll i=0;i<n;i++){
        cin >> x[i];
        v.clear();
        x[i] %= mod;
        if(x[i] == 0)x[i] += mod;
        v.pb(1); v.pb(x[i] - 1);
        G.pb(v);
    }
    while(G.size() >= 2){
        // 分割統治パート
        if(G[0].size() <= 32 && G[1].size() <= 32){
            vector<ll> v(G[0].size() + G[1].size());
            for(ll i=0;i<G[0].size();i++){
                for(ll j=0;j<G[1].size();j++){
                    v[i+j] += G[0][i] * G[1][j];
                    v[i+j] %= mod;
                }
            }
            G.pb(v);
        }else{
            G.pb(NTT::conv(mod, 3ll, G[0], G[1]));
        }
        G.pop_front();
        G.pop_front();
    }
    for(ll i=0;i<q;i++){
        cin >> y[i];
        ll degree = n - y[i];
        p(G[0][degree]);
    }
    return;
}


int main(){
    // init();
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    ll q, testcase = 1;
    if(multicase){
        cin >> q;
    }else{
        q = 1; 
    }
    while(q--){
        // pu("Case ");pu("#");pu(testcase);pu(": ");
        solve();
        testcase++;
    }
    // solve();
    return 0;
}