/**
 *   @FileName	a.cpp
 *   @Author	kanpurin
 *   @Created	2020.05.30 02:19:06
**/

#include "bits/stdc++.h" 
using namespace std; 
typedef long long ll;

constexpr int MOD = 1e9 + 7;
struct mint {
private:
    long long x;
public:
    mint(long long x = 0) : x((MOD + x) % MOD) {}
    mint(std::string& s) {
        long long z = 0;
        for (int i = 0; i < s.size(); i++) {
            z *= 10;
            z += s[i] - '0';
            z %= MOD;
        }
        this->x = z;
    }
    mint& operator+=(const mint& a) {
        if ((x += a.x) >= MOD) x -= MOD;
        return *this;
    }
    mint& operator-=(const mint& a) {
        if ((x += MOD - a.x) >= MOD) x -= MOD;
        return *this;
    }
    mint& operator*=(const mint& a) {
        (x *= a.x) %= MOD;
        return *this;
    }
    mint& operator/=(const mint& a) {
        long long n = MOD - 2;
        mint u = 1, b = a;
        while (n > 0) {
            if (n & 1) {
                u *= b;
            }
            b *= b;
            n >>= 1;
        }
        return *this *= u;
    }
    mint operator+(const mint& a) const {
        mint res(*this);
        return res += a;
    }
    mint operator-(const mint& a) const {
        mint res(*this);
        return res -= a;
    }
    mint operator*(const mint& a) const {
        mint res(*this);
        return res *= a;
    }
    mint operator/(const mint& a) const {
        mint res(*this);
        return res /= a;
    }
    friend std::ostream& operator<<(std::ostream& os, const mint& n) {
        return os << n.x;
    }
    bool operator==(const mint& a) const {
        return this->x == a.x;
    }
};
// 素因数分解 O(√n)以下
// (素因数,個数)
template<typename T>
vector<pair<T,int>> prime_factorization(T n) {
    vector<pair<T, int>> res;
    for (T i = 2; i*i <= n; i++) {
        int cnt = 0;
        while (n % i == 0) {
            n /= i;
            cnt++;
        }
        if (cnt > 0) res.push_back({i,cnt});
    }
    if (n > 1) res.push_back({n,1});
    return res;
}
// pow
template < typename T, typename U >
T pow(T k, U n, T unity = 1) {
    while (n > 0) {
        if (n & 1) {
            unity *= k;
        }
        k *= k;
        n >>= 1;
    }
    return unity;
}
int main() {
    int n, k;
    cin >> n >> k;
    map<int, priority_queue< int > > pq;
    for (int i = 0; i < n; i++) {
        int a;
        cin >> a;
        auto v = prime_factorization(a);
        for(auto p : v) {
            pq[p.first].push(p.second);
        }
    }
    mint ans = 1;
    for (auto p : pq) {
        int cnt = 0;
        for(int i = 0; i < k; i++) {
            if (pq[p.first].empty()) break;
            int q = pq[p.first].top(); pq[p.first].pop();
            cnt += q;
        }
        ans *= pow(mint(p.first), cnt);
    }
    cout << ans << endl;
    return 0;
}