#pragma GCC optimize("O3") #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; using ll = long long; using P = pair; using T = tuple; template inline T chmax(T &a, const T b) {return a = (a < b) ? b : a;} template inline T chmin(T &a, const T b) {return a = (a > b) ? b : a;} constexpr int MOD = 1e9 + 7; constexpr int inf = 1e9; constexpr long long INF = 1e18; #define all(a) (a).begin(), (a).end() int dx[] = {1, 0, -1, 0}; int dy[] = {0, 1, 0, -1}; ll modpow(ll a, ll b){ if(b == 0) return 1; else if(b % 2 == 0){ ll d = modpow(a, b / 2) % MOD; return (d * d) % MOD; } else{ return (a * modpow(a, b - 1)) % MOD; } } const int MAX_N = 400020; ll fact[MAX_N], finv[MAX_N]; ll comb(int n, int r){ if(n < r || r < 0) return 0; return fact[n] * finv[n-r] % MOD * finv[r] % MOD; } void comb_init(int n){ fact[0] = finv[0] = 1; for(int i=1; i<=n; i++){ fact[i] = (fact[i-1] * i) % MOD; finv[i] = modpow(fact[i], MOD - 2); } } int main(){ cin.tie(0); ios::sync_with_stdio(false); int n, m, k; cin>>n>>m>>k; comb_init(400010); ll ans = 0; for(int i=1; i<=m; i++){ if(n < i) break; int sum = (n - i) + (m - i); if(sum < k) continue; ans += (comb(m - 1, m - i) * comb(n, i) % MOD); ans %= MOD; } ans *= fact[n-1]; ans %= MOD; ans *= fact[m]; ans %= MOD; cout << ans << endl; return 0; }