#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ld = long double;
 
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ld = long double;

void solve(ll a, ll b, ll c)
{
    ld A=a;
    ld B=b;
    ld C=c;
    // 判別式
    ld D = B*B - 4.0L*A*C;
    cout << fixed << setprecision(15);
    if(a==0 && b == 0 && c==0)
    {
        cout << "-1\n";
    }
    else if((a==0 && b==0) || D<0)
    {
        cout << "0\n";
    }
    else if(a==0)
    {
        // x = -c/b | a==0
        cout << "1\n" << -C/B << '\n';
    }
    else if(D<0.1)
    {
        // x = -b / 2a
        cout << "1\n" << -B/(2.0L*A) << '\n';
    }
    else
    {
        ll sq = sqrt(D);
        ld x1 = 0; // +
        ld x2 = 0; // -
        if(b%(2*a)==0 && sq*sq==D)
        {
            x1 = b/(2*a) + static_cast<ld>(sq)/(2.0L*A);
            x2 = b/(2*a) - static_cast<ld>(sq)/(2.0L*A);
        }
        else if(b%(2*a)==0)
        {
            x1 = b/(2*a) + sqrt(D)/(2.0L*A);
            x2 = b/(2*a) - sqrt(D)/(2.0L*A);
        }
        else if(sq*sq==D)
        {
            x1 = B/(2.0L*A) + static_cast<ld>(sq)/(2.0L*A);
            x2 = B/(2.0L*A) - static_cast<ld>(sq)/(2.0L*A);
        }
        else
        {
            x1 = (-B + sqrt(D)) / (2.0L * A);
            x2 = (-B - sqrt(D)) / (2.0L * A);
        }

        cout << "2\n" << min(x1, x2) << '\n' << max(x1, x2) << '\n';
    }
    
    return;
}

int main()
{
    ios::sync_with_stdio(false);
    cin.tie(0);
    int a, b, c;
    cin >> a >> b >> c;
    solve(a, b, c);

    return 0;
}