#include #define rep(i,n) for(int i=(0);i<(n);i++) using namespace std; typedef long long ll; typedef long double ld; template bool chmax(T &a, const T &b) { if (a bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; } const ll MOD = 1e9 + 7; ll modpow(ll a, ll b){ if(b == 0) return 1; if(b % 2 == 1) return a * modpow(a, b - 1) % MOD; ll d = modpow(a, b / 2) % MOD; return d * d % MOD; } typedef vector> mat; void print(mat A){ rep(i, A.size()){ rep(j, A[i].size()){ cout << A[i][j] << (j == A[i].size()-1 ? "\n" : " "); } } } mat mmul(mat A, mat B){ int n = A.size(); int l = A[0].size(); int m = B[0].size(); mat C(n, vector(m, 0)); for(int i = 0; i < n; i++){ for(int j = 0; j < m; j++){ for(int k = 0; k < l; k++){ C[i][j] += A[i][k] * B[k][j]; C[i][j] %= MOD; } } } return C; } mat mE(int n){ mat A(n, vector(n, 0)); for(int i = 0; i < n; i++){ A[i][i] = 1LL; } return A; } mat mpow(mat A, ll x){ int n = A.size(); if(x == 0) return mE(n); if(x % 2 == 1) return mmul(A, mpow(A, x - 1)); mat B = mpow(A, x / 2); return mmul(B, B); } int main(){ cin.tie(0); ios::sync_with_stdio(false); ll n; cin >> n; vector p(7, 0); ll d = modpow(6ll, MOD - 2); p[1] = d; ll sm = p[1]; rep(i, 5){ p[i+2] = d * sm % MOD + d; p[i+2] %= MOD; sm += p[i+2]; sm %= MOD; } if(n <= 6){ cout << p[n] << endl; }else{ mat A = vector>(6, vector(6)); rep(j, 6) A[0][j] = d; for(int i = 1; i < 6; i++){ rep(j, 6) A[i][j] = (j == i - 1 ? 1 : 0); } mat x = vector>(6, vector(1)); rep(i, 6) x[i][0] = p[6 - i]; cout << mmul(mpow(A, n - 6), x)[0][0] << endl; } }