#include <bits/stdc++.h>
#ifdef _DEBUG
#include "debug.hpp"
#else
#define debug(...)
#endif
#define REP(i, m, n) for(int i = (int)(m); i < (int)(n); ++i)
#define rep(i, n) REP(i, 0, n)
using namespace std;
using ll = long long;
using ld = long double;
using pll = pair<ll, ll>;
template<class T, class U> inline bool chmax(T &a, const U &b) { if(a < b) { a = b; return true; } return false; }
template<class T, class U> inline bool chmin(T &a, const U &b) { if(a > b) { a = b; return true; } return false; }

constexpr int MOD = 1e9+7;
//constexpr int MOD = 998244353;

struct mint {
long long x;
  mint(long long x = 0) noexcept : x((x%MOD + MOD) % MOD) {}

  // basis
  mint operator-() const { return mint(-x); }
  mint& operator+=(const mint a) noexcept { if((x += a.x) >= MOD) x -= MOD; return *this; }
  mint& operator-=(const mint a) noexcept { if((x += MOD-a.x) >= MOD) x -= MOD; return *this; }
  mint& operator*=(const mint a) noexcept { (x *= a.x) %= MOD; return *this; }
  mint operator+(const mint a) const noexcept { return mint(*this) += a; }
  mint operator-(const mint a) const noexcept { return mint(*this) -= a; }
  mint operator*(const mint a) const noexcept { return mint(*this) *= a; }
  mint mpow(long long t) const noexcept {
    if(!t) return 1;
    mint a = mpow(t>>1);
    a *= a;
    if(t&1) a *= *this;
    return a;
  }

  // for prime MOD
  mint inv() const noexcept { return mpow(MOD-2); }
  mint& operator/=(const mint a) noexcept { return *this *= a.inv(); }
  mint operator/(const mint a) const noexcept { return mint(*this) /= a; }

  // comparison
  bool operator==(const mint &a) const noexcept { return this->x == a.x; }
  bool operator!=(const mint &a) const noexcept { return this->x != a.x; }

  // I/O stream
  friend istream& operator>>(istream& is, mint& a) noexcept { return is >> a.x; }
  friend ostream& operator<<(ostream& os, const mint& a) noexcept { return os << a.x; }
};
// additional
mint mpow(const long long &a, long long n) noexcept { return mint(a).mpow(n); }
mint mpow(const mint &a, long long n) noexcept { return a.mpow(n); }


int n, d, k;
mint dp[310][100000], sum[310][100000];

int main() {
  cin.tie(0); ios::sync_with_stdio(false);
  cin >> n >> d >> k;
  dp[0][0] = 1;
  rep(j, k) sum[0][j+1] += sum[0][j]+dp[0][j];
  rep(i, n) rep(j, k) {
    dp[i+1][j+1] = sum[i][j+1]-sum[i][max(0, j-d+1)];
    sum[i+1][j+2] += sum[i+1][j+1]+dp[i+1][j+1];
  }
  cout << dp[n][k] << '\n';
  return 0;
}