#include <bits/stdc++.h>
using namespace std;
#define F first
#define S second
#define R cin>>
#define ll long long
#define ln cout<<'\n'
#define in(a) insert(a)
#define pb(a) push_back(a)
#define pd(a) printf("%.10f\n",a)
#define mem(a) memset(a,0,sizeof(a))
#define all(c) (c).begin(),(c).end()
#define iter(c) __typeof((c).begin())
#define rrep(i,n) for(ll i=(ll)(n)-1;i>=0;i--)
#define REP(i,m,n) for(ll i=(ll)(m);i<(ll)(n);i++)
#define rep(i,n) REP(i,0,n)
#define tr(it,c) for(iter(c) it=(c).begin();it!=(c).end();it++)
ll check(ll n,ll m,ll x,ll y){return x>=0&&x<n&&y>=0&&y<m;}void pr(){ln;}
template<class A,class...B>void pr(const A &a,const B&...b){cout<<a<<(sizeof...(b)?" ":"");pr(b...);}
template<class A>void PR(A a,ll n){rep(i,n)cout<<(i?" ":"")<<a[i];ln;}
const ll MAX=1e9+7,MAXL=1LL<<61,dx[8]={-1,0,1,0,-1,-1,1,1},dy[8]={0,1,0,-1,-1,1,1,-1};
typedef pair<ll,ll> P;

int dp[1001][4001];

void Main() {
  ll n;
  cin >> n;
  int a[n];
  rep(i,n) {
    cin >> a[i];
    a[i]+=2000;
  }
  rep(i,n)rep(j,4001)dp[i][j]=MAX;
  rep(i,4000) dp[0][i]=abs(i-a[0]);
  REP(i,1,n) {
    int M=MAX;
    rep(j,4000) {
      M=min(M,dp[i-1][j]);
      dp[i][j]=min(dp[i][j],M+(int)abs(j-a[i]));
    }
  }
  int ans=MAX;
  rep(i,4000) ans=min(ans,dp[n-1][i]);
  pr(ans);
}

int main(){ios::sync_with_stdio(0);cin.tie(0);Main();return 0;}