#include <cstdio>
#include <cstring>
#include <iostream>
#include <string>
#include <cmath>
#include <bitset>
#include <vector>
#include <map>
#include <set>
#include <queue>
#include <deque>
#include <algorithm>
#include <complex>
#include <unordered_map>
#include <unordered_set>
#include <random>
#include <cassert>
#include <fstream>
#include <utility>
#include <functional>
#include <time.h>
#include <stack>
#include <array>
#define popcount __builtin_popcount
using namespace std;
typedef long long int ll;
typedef pair<int, ll> P;
int n, k;
int a[100010];
ll ans;
const int INF=1e9+7;
const ll INFL=1e18;
void solve(int l, int r){
	if(l==r){
		if(a[l]+a[r]==k) ans++;
		return;
	}
	int m=(l+r)/2;
	int mn=INF, cnt=0;
    map<int, vector<P>> mp;
	for(int i=m; i>=l; i--){
		if(mn>a[i]){
			mn=a[i];
		}
        mp[a[i]].push_back({mn, m+1-i});
	}
    for(auto &p:mp){
        sort(p.second.begin(), p.second.end());
        for(int i=1; i<p.second.size(); i++) p.second[i].second+=p.second[i-1].second;
    }
	mn=INF, cnt=0;
	for(int i=m+1; i<=r; i++){
		if(mn>a[i]){
			mn=a[i], cnt=1;
		}else if(mn==a[i]){
			cnt++;
		}
		if(cnt==1){
			auto itr=mp.find(k-a[i]);
            if(itr!=mp.end()){
                int t=upper_bound(itr->second.begin(), itr->second.end(), P(mn, INFL))-itr->second.begin();
                ans+=((ll)itr->second.size()-t)*(i-m);
                if(t>0) ans+=itr->second.back().second-itr->second[t-1].second;
                else ans+=itr->second.back().second;
            }
		}
	}
    mp.clear();
    mn=INF, cnt=0;
	for(int i=m+1; i<=r; i++){
		if(mn>a[i]){
			mn=a[i];
		}
        mp[a[i]].push_back({mn, i-m});
	}
    for(auto &p:mp){
        sort(p.second.begin(), p.second.end());
        for(int i=1; i<p.second.size(); i++) p.second[i].second+=p.second[i-1].second;
    }
	mn=INF, cnt=0;
	for(int i=m; i>=l; i--){
		if(mn>a[i]){
			mn=a[i], cnt=1;
		}else if(mn==a[i]){
			cnt++;
		}
		if(cnt==1){
			auto itr=mp.find(k-a[i]);
            if(itr!=mp.end()){
                int t=upper_bound(itr->second.begin(), itr->second.end(), P(mn, INFL))-itr->second.begin();
                ans+=((ll)itr->second.size()-t)*(m+1-i);
                if(t>0) ans+=itr->second.back().second-itr->second[t-1].second;
                else ans+=itr->second.back().second;
            }
		}
	}
	solve(l, m); solve(m+1, r);
}
int main()
{
	cin>>n>>k;
	for(int i=0; i<n; i++){
		cin>>a[i];
	}
	solve(0, n-1);
	cout<<ans<<endl;
	return 0;
}