#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include template inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; } template inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; } constexpr long long MAX = 5100000; constexpr long long INF = 1LL << 60; constexpr int inf = 1000000007; constexpr long long mod = 1000000007LL; //constexpr long long mod = 998244353LL; const long double PI = acos((long double)(-1)); using namespace std; typedef unsigned long long ull; typedef long long ll; typedef long double ld; struct mint { long long x; mint(long long x = 0) :x((x% mod + mod) % mod) {} mint& operator+=(const mint a) { if ((x += a.x) >= mod) x -= mod; return *this; } mint& operator-=(const mint a) { if ((x += mod - a.x) >= mod) x -= mod; return *this; } mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this; } mint operator+(const mint a) const { mint res(*this); return res += a; } mint operator-(const mint a) const { mint res(*this); return res -= a; } mint operator*(const mint a) const { mint res(*this); return res *= a; } mint pow(ll t) const { if (!t) return 1; mint a = pow(t >> 1); a *= a; if (t & 1) a *= *this; return a; } // for prime mod mint inv() const { return pow(mod - 2); } mint& operator/=(const mint a) { return (*this) *= a.inv(); } mint operator/(const mint a) const { mint res(*this); return res /= a; } }; int main() { /* cin.tie(nullptr); ios::sync_with_stdio(false); */ constexpr ll b = inf - 7; ll n; scanf("%lld", &n); vector a(n); for (int i = 0; i < n; i++) scanf("%lld", &a[i]); for (int i = 0; i < n; i++) if (a[i] == 0) { puts("0"); return 0; } mint res = 1; ll cur = 1; mint rui = 1; int right = 0; for (int left = 0; left < n; left++) { while (right < n and cur * a[right] < b) { cur *= a[right]; rui *= cur; right++; } res *= rui; if (left == right) right++; else cur /= a[left], rui /= mint(a[left]).pow(right - left); } cout << res.x << "\n"; return 0; }