#include <bits/stdc++.h>
using namespace std;
typedef signed long long ll;

#undef _P
#define _P(...) (void)printf(__VA_ARGS__)
#define FOR(x,to) for(x=0;x<(to);x++)
#define FORR(x,arr) for(auto& x:arr)
#define ITR(x,c) for(__typeof(c.begin()) x=c.begin();x!=c.end();x++)
#define ALL(a) (a.begin()),(a.end())
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
//-------------------------------------------------------

int N;
vector<pair<int,int>> E[200005];
int P[21][200005],D[200005];
ll AD[202020];

int Q;
int X,Y;

void dfs(int cur) {
	FORR(e,E[cur]) if(e.first!=P[0][cur]) {
		D[e.first]=D[cur]+1;
		AD[e.first]=AD[cur]+e.second;
		P[0][e.first]=cur;
		dfs(e.first);
	}
}

int lca(int a,int b) {
	int ret=0,i,aa=a,bb=b;
	if(D[aa]>D[bb]) swap(aa,bb);
	for(i=19;i>=0;i--) if(D[bb]-D[aa]>=1<<i) bb=P[i][bb];
	for(i=19;i>=0;i--) if(P[i][aa]!=P[i][bb]) aa=P[i][aa], bb=P[i][bb];
	return (aa==bb)?aa:P[0][aa];               // vertex
}

void solve() {
	int i,j,k,l,r,x,y; string s;
	
	cin>>N;
	FOR(i,N-1) {
		cin>>x>>y>>r;
		E[x-1].push_back({y-1,r});
		E[y-1].push_back({x-1,r});
	}

	//0以外を根にするならP[0][root]=rootが必要
	dfs(0);
	FOR(i,19) FOR(x,N) P[i+1][x]=P[i][P[i][x]];
	
	cin>>Q;
	while(Q--) {
		cin>>X>>Y;
		X--,Y--;
		int lc=lca(X,Y);
		cout<<(AD[X]+AD[Y]-2*AD[lc])<<endl;
	}
	
}


int main(int argc,char** argv){
	string s;int i;
	if(argc==1) ios::sync_with_stdio(false), cin.tie(0);
	FOR(i,argc-1) s+=argv[i+1],s+='\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);
	cout.tie(0); solve(); return 0;
}