#include #define rep(i,n) for(int i = 0; i < (n); ++i) #define drep(i,n) for(int i = (n)-1; i >= 0; --i) #define srep(i,s,t) for (int i = s; i < t; ++i) using namespace std; typedef long long int ll; typedef pair P; #define yn {puts("Yes");}else{puts("No");} struct edge{ int to, cost; }; const int INF = 1001001001; const int MAX_N = 200005; const int MAX_V = 200005; vector G[MAX_V]; int d[MAX_V]; void dijkstra(int s){ // greater

を指定することでfirstが小さい順に取り出せるようにする priority_queue, greater

> que; fill(d, d+MAX_V, INF); d[s] = 0; que.push(P(0, s)); while(!que.empty()){ P p = que.top(); que.pop(); int v = p.second; for(int i=0; i d[v] + e.cost){ d[e.to] = d[v] + e.cost; que.push(P(d[e.to], e.to)); } } } } int main() { int n, c, v; cin >> n >> c >> v; int s[v], t[v], y[v], m[v]; rep(i,v){ cin >> s[i]; s[i]--; } rep(i,v){ cin >> t[i]; t[i]--; } rep(i,v)cin >> y[i]; rep(i,v)cin >> m[i]; rep(i,v){ int from = s[i]; int to = t[i]; int cost = m[i]; int money = y[i]; rep(j,400){ if(j - money < 0)continue; edge e; e.to = to * 400 + (j - money); e.cost = cost; G[from*400 + j].push_back(e); } } dijkstra(c); int ans = 1001001001; rep(i,400)ans = min(ans, d[(n-1)*400+i]); if(ans >= INF)ans = -1; cout << ans << endl; return 0; }