# frozen_string_literal: true

def solve
  x = (N[0..1].to_i + (N[2].to_i <= 4 ? 0 : 1)).to_s.chars
  case x.size
  when 2
    ab = x.join('.')
    c = N.size - 1
    %(#{ab}*10^#{c})
  when 3
    c = N.size
    %(1.0*10^#{c})
  end
end

N = gets.chomp

puts solve