#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i)) #define rer(i,l,u) for(int (i)=(int)(l);(i)<=(int)(u);++(i)) #define reu(i,l,u) for(int (i)=(int)(l);(i)<(int)(u);++(i)) #if defined(_MSC_VER) || __cplusplus > 199711L #define aut(r,v) auto r = (v) #else #define aut(r,v) __typeof(v) r = (v) #endif #define each(it,o) for(aut(it, (o).begin()); it != (o).end(); ++ it) #define all(o) (o).begin(), (o).end() #define pb(x) push_back(x) #define mp(x,y) make_pair((x),(y)) #define mset(m,v) memset(m,v,sizeof(m)) #define INF 0x3f3f3f3f #define INFL 0x3f3f3f3f3f3f3f3fLL using namespace std; typedef vector vi; typedef pair pii; typedef vector > vpii; typedef long long ll; template inline void amin(T &x, U y) { if(y < x) x = y; } template inline void amax(T &x, U y) { if(x < y) x = y; } struct FenwickTree { typedef int T; vector v; void init(int n) { v.assign(n, 0); } void add(int i, T x) { for(; i < (int)v.size(); i |= i+1) v[i] += x; } T sum(int i) const { //[0, i) T r = 0; for(-- i; i >= 0; i = (i & (i+1)) - 1) r += v[i]; return r; } T sum(int left, int right) const { //[left, right) return sum(right) - sum(left); } }; int main() { int N; while(~scanf("%d", &N)) { vector A(N); for(int i = 0; i < N; ++ i) scanf("%d", &A[i]); vector values = A; sort(values.begin(), values.end()); values.erase(unique(values.begin(), values.end()), values.end()); for(vector::iterator it = A.begin(); it != A.end(); ++ it) *it = lower_bound(values.begin(), values.end(), *it) - values.begin(); int X = values.size(); vi cnt(X, 0), sum(X+1, 0); rep(i, N) ++ cnt[A[i]]; rep(i, X) sum[i + 1] = sum[i] + cnt[i]; FenwickTree ft; ft.init(X); vi curcnt(X, 0); vector cursum(X, 0); vi firstpos(X, -1); ll ans = 0; rep(i, N) { int a = A[i]; int xL = ft.sum(a); int yL = i - xL - curcnt[a]; ans += (ll)xL * (sum[a] - xL); ans += (ll)yL * (sum[X] - sum[a + 1] - yL); ans -= (ll)curcnt[a] * (i-1) - cursum[a]; ft.add(a, 1); ++ curcnt[a]; cursum[a] += i; } rep(a, X) { int n = cnt[a]; ans += (ll)n * (n-1) * (n-2) / 6; } printf("%lld\n", ans); } return 0; }