#include #define fi first #define se second #define rep(i,n) for(int i = 0; i < (n); ++i) #define rrep(i,n) for(int i = 1; i <= (n); ++i) #define drep(i,n) for(int i = (n)-1; i >= 0; --i) #define srep(i,s,t) for (int i = s; i < t; ++i) #define rng(a) a.begin(),a.end() #define rrng(a) a.rbegin(),a.rend() #define maxs(x,y) (x = max(x,y)) #define mins(x,y) (x = min(x,y)) #define isin(x,l,r) ((l) <= (x) && (x) < (r)) #define pb push_back #define eb emplace_back #define sz(x) (int)(x).size() #define pcnt __builtin_popcountll #define uni(x) x.erase(unique(rng(x)),x.end()) #define snuke srand((unsigned)clock()+(unsigned)time(NULL)); #define show(x) cout<<#x<<" = "< > #define bn(x) ((1< #define vv(T) v(v(T)) using namespace std; typedef long long int ll; typedef unsigned uint; typedef unsigned long long ull; typedef pair P; typedef tuple T; typedef vector vi; typedef vector vvi; typedef vector vl; typedef vector

vp; typedef vector vt; inline int getInt() { int x; scanf("%d",&x); return x;} templateinline istream& operator>>(istream&i,v(T)&v) {rep(j,sz(v))i>>v[j];return i;} templatestring join(const v(T)&v) {stringstream s;rep(i,sz(v))s<<' '<inline ostream& operator<<(ostream&o,const v(T)&v) {if(sz(v))o<inline istream& operator>>(istream&i,pair&v) {return i>>v.fi>>v.se;} templateinline ostream& operator<<(ostream&o,const pair&v) {return o<inline ll suma(const v(T)& a) { ll res(0); for (auto&& x : a) res += x; return res;} const double eps = 1e-10; const ll LINF = 1001002003004005006ll; const int INF = 1001001001; #define dame { puts("-1"); return 0;} #define yn {puts("Yes");}else{puts("No");} const int MX = 3005; // sliding queue struct SQ { // max typedef ll TT; typedef pair TP; deque q; void add(int i, TT x) { while (sz(q) && q.back().fi <= x) q.pop_back(); q.pb(TP(x,i)); } TT get(int i) { // i <= pos while (sz(q) && q[0].se < i) q.pop_front(); if (sz(q)) return q[0].fi; return -LINF; // INF! } }; // ll dp[MX][MX]; int main() { int n,k,m; scanf("%d%d%d",&n,&k,&m); vl a(n); cin>>a; vl s(n+1); rep(i,n) s[i+1] = s[i]+a[i]; rep(i,k+1)rep(j,n+1) dp[i][j] = -LINF; dp[0][0] = 0; rep(i,k) { SQ da, db; rep(j,n) { da.add(j,dp[i][j]-s[j]); db.add(j,dp[i][j]+s[j]); ll now = da.get(j+1-m)+s[j+1]; maxs(now, db.get(j+1-m)-s[j+1]); dp[i+1][j+1] = now; } } ll ans = dp[k][n]; cout<