#pragma region
#pragma GCC target("avx2")
#pragma GCC optimize("03")
#pragma GCC optimize("unroll-loops")
#include <bits/stdc++.h>
using namespace std; typedef long double ld; typedef long long ll;
typedef unsigned long long ull;
#define endl "\n"
#define FOR(i,a,b) for(int i=(a);i<=(b);i++)
#define PII pair<int, int>
#define PLL pair<ll, ll>
#define VPII vector<PII>
#define VPLL vector<PLL>
#define ALL(x) (x).begin(), (x).end()
constexpr int INF=1<<30; constexpr ll LINF=1LL<<60; constexpr ll mod=1e9+7; constexpr int NIL = -1;
template<class T>inline bool chmax(T &a, const T &b) { if (a<b) { a = b; return 1; } return 0; }
template<class T>inline bool chmin(T &a, const T &b) { if (b<a) { a = b; return 1; } return 0; }
#pragma endregion
//-------------------
const int MX = 12;
int a[MX][MX];
int n,m,k;

vector<int> v1;
vector<int> v2;

void dfs(int i, int ed, int cur, vector<int>& v) {
    if(i==ed) {
        for(int j=0; j<m; j++) {
            v.emplace_back(a[i][j]+cur);
        }
        return;
    }
    for(int j=0; j<m; j++) {
        // cout << i << " "  << j << endl;
        dfs(i+1, ed, cur+a[i][j], v);
    }
}


int main(){
    cin.tie(0); ios::sync_with_stdio(false); //cout << fixed << setprecision(15);
    cin >> n >> m >> k;
    FOR(i,0,n-1) {
        FOR(j,0,m-1) {
            cin >> a[i][j];
        }
    }

    int mid = n/2;

    if(n > 1) {
        dfs(0, mid-1, 0, v1);
        dfs(mid, n-1, 0, v2);
        sort(ALL(v1));
        sort(ALL(v2));
        int ans = INF;
        // FOR(i,0,100) cout << v2[i] << " ";
        // cout << v1[0] << v2[0] << mid << endl;
        for(auto &e: v1){
            int now = k - e;
            if(now <= 0) continue;
            auto resi = upper_bound(ALL(v2), now);
            if(resi != v2.begin()) chmin(ans, now - *(resi-1));
        }

        if(ans != INF) cout << ans << endl;
        else cout << -1 << endl;
    } else {
        FOR(i,0,m-1) v1.push_back(a[0][i]);
        auto resi = upper_bound(ALL(v1), k);
        if(resi != v1.begin()) cout << k - *(resi-1) << endl;
        else cout << -1 << endl;
    }
    return 0;
}