#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define ld long double
#define REP(i,m,n) for(int i=(int)(m); i<(int)(n); i++)
#define rep(i,n) REP(i,0,n)
#define RREP(i,m,n) for(int i=(int)(m); i>=(int)(n); i--)
#define rrep(i,n) RREP(i,n-1,0)
#define all(v) v.begin(), v.end()
const int inf = 1e9+7;
const ll longinf = 1LL<<60;
const ll mod = 1e9+7;
const ld eps = 1e-10;

void find_divisor(ll N, vector<ll>& divisor) {
  for(int i=1; i<=sqrt(N); i++) {
    if(N % i == 0)
      divisor.push_back(i);
  }
  int n = divisor.size();
  for(int i=n-1; i>=0; i--) {
    if(N != (ll)pow(divisor[i], 2))
      divisor.push_back(N / divisor[i]);
  }
}
ll modpow(ll a, ll N, ll mod=mod) {
  ll ans = 1;
  ll tmp = a;
  while(N > 0) {
    if(N % 2 == 1) (ans *= tmp) %= mod;
    (tmp *= tmp) %= mod;
    N /= 2;
  }
  return ans;
}
void solve() {
  ll a, p; cin >> a >> p;
  vector<ll> div;
  find_divisor(p, div);
  if(div.size() != 2) cout << -1 << endl;
  else {
    ll ans = a;
    rep(i, p) ans = modpow(ans, i+1)%p;
    cout << ans << endl;
  }
}
int main() {
  cin.tie(0);
  ios::sync_with_stdio(false);
  int t; cin >> t;
  while(t--) {
    solve();
  }
  return 0;
}