#include<bits/stdc++.h>
using namespace std;
#define int long long
#define ii pair <int, int>
#define app push_back
#define all(a) a.begin(), a.end()
#define bp __builtin_popcountll
#define ll long long
#define mp make_pair
#define f first
#define s second
#define Time (double)clock()/CLOCKS_PER_SEC
#define debug(x) std::cout << #x << ": " << x << '\n';

const int MOD = 1000 * 1000 * 1000 + 7;
int mod(int n) {
    n %= MOD;
    if (n < 0) return n + MOD;
    else return n;
}   
int fp(int a, int p) {
    int ans = 1, c = a;
    for (int i = 0; (1ll << i) <= p; ++i) {
        if ((p >> i) & 1) ans = mod(ans * c);
        c = mod(c * c);
    }   
    return ans;
}   
int dv(int a, int b) { return mod(a * fp(b, MOD - 2)); }

struct Point {
    int x, y;
    Point operator - (Point p) {
        return {x - p.x, y - p.y};  
    }  
    int operator * (Point p) {
        return x * p.y - y * p.x;
    }   
    int operator % (Point p) {
        return x * p.x + y * p.y;
    }
    bool operator == (Point p) {
        return x == p.x && y == p.y;
    }   
};  

bool col(Point a, Point b) {
    return a % b >= 0 && a * b == 0;
}   

signed main() {
    #ifdef HOME
    freopen("input.txt", "r", stdin);
    #else
    #define endl '\n'
    ios_base::sync_with_stdio(0); cin.tie(0);
    #endif    
    int n;
    cin >> n;
    vector <Point> a(n);
    for (int i = 0; i < n; ++i) {
        cin >> a[i].x >> a[i].y;
    }   
    int ans = 0;
    for (int s = 0; s < n; ++s) {
        vector <Point> v;
        for (int i = 0; i < n; ++i) 
            if (!(a[s] == a[i]))
                v.app(a[i] - a[s]);
        auto comp = [] (Point a, Point b) { return atan2(a.y, a.x) < atan2(b.y, b.x); };
        sort(all(v), comp);
        int sz = v.size();
        for (int i = 0; i < sz; ++i)
            v.app(v[i]);
        int j = 0;
        for (int i = 0; i < sz; ++i) {
            j = max(j, i);
            while (j + 1 < i + sz && v[i] * v[j+1] >= 0)
                ++j;
            for (int k = i; k <= j; ++k) {
                ans += v[i] * v[k];
            }                    
        }   
    }
    cout << dv(ans, 3) << endl;
}