#include <bits/stdc++.h>
using namespace std;

inline int toInt(string s) {int v; istringstream sin(s);sin>>v;return v;}
template<class T> inline string toString(T x) {ostringstream sout;sout<<x;return sout.str();}

typedef long long ll;
typedef vector<int> VI;
typedef vector<VI> VVI;
typedef vector<long long> VL;
typedef vector<vector<long long>> VVL;
typedef vector<string> VS;
typedef pair<int, int> P;
typedef tuple<int,int,int> tpl;

#define ALL(a)  (a).begin(),(a).end()
#define SORT(c) sort((c).begin(),(c).end())
#define REVERSE(c) reverse((c).begin(),(c).end())
#define EXIST(m,v) (m).find((v)) != (m).end()
#define LB(a,x) lower_bound((a).begin(), (a).end(), x) - (a).begin()
#define UB(a,x) upper_bound((a).begin(), (a).end(), x) - (a).begin()

#define FOR(i,a,b) for(int i=(a);i<(b);++i)
#define REP(i,n)  FOR(i,0,n)
#define RFOR(i,a,b) for(int i=(a)-1;i>=(b);--i)
#define RREP(i,n) RFOR(i,n,0)

#define en "\n"

constexpr double EPS = 1e-9;
constexpr double PI  = 3.1415926535897932;
constexpr int INF = 2147483647;
constexpr long long LINF = 1LL<<60;
constexpr long long MOD = 1000000007; // 998244353;

#define dump(x)  cerr << #x << " = " << (x) << endl;
#define debug(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ")" << " " << __FILE__ << endl;

template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; }

void Main(){
    int N,M,K; cin >> N >> M >> K;
    VI a(N), b(M); REP(i,N) cin >> a[i]; REP(i,M) cin >> b[i];

    VL na(1024,0), nb(1024,0);
    int s = 0; na[0] = nb[0] = 1;
    REP(i,N){
        s ^= a[i];
        na[s]++;
    }
    s = 0;
    REP(i,M){
        s ^= b[i];
        nb[s]++;
    }

    VL A(1024,0),B(1024,0);
    REP(i,1024)FOR(j,i,1024){
        if(i == j){
            (A[i^j] += na[i]*(na[j]-1)/2) %= MOD;
            (B[i^j] += nb[i]*(nb[j]-1)/2) %= MOD;
        }
        else{
            (A[i^j] += na[i]*na[j]) %= MOD;
            (B[i^j] += nb[i]*nb[j]) %= MOD;
        }
    }

    ll ans = 0;
    REP(i,1024){
        (ans += A[i]*B[K^i]) %= MOD;
    }
    cout << ans << en;
    return;
}

int main(void){
    cin.tie(0);cout.tie(0);ios_base::sync_with_stdio(0);cout<<fixed<<setprecision(15);
    int t=1; //cin>>t;
    REP(_,t) Main();
    return 0;
}