#include <bits/stdc++.h>
#define rep(i,n) for (int i = 0; i < (int)(n); i ++)
#define irep(i,n) for (int i = (int)(n) - 1;i >= 0;--i)
using namespace std;
using ll = long long;
using PL = pair<ll,ll>;
using P = pair<int,int>;
constexpr int INF = 1000000000;
constexpr long long HINF = 1000000000000000;
constexpr long long MOD = 1000000007;// = 998244353;
constexpr double EPS = 1e-4;
constexpr double PI = 3.14159265358979;

struct UnionFind {
    int N;
    vector<int> parents;

    UnionFind(int _N) : N(_N){
        parents.assign(N,-1);
    }

    int find(int x) { //xの親を返す
        if (parents[x] < 0) return x;
        return parents[x] = find(parents[x]);
    }
    
    void unite(int x, int y) {  //xとyの含むグループを併合
        int px = find(x);
        int py = find(y);
        if (parents[px] > parents[py]) swap(px,py); 
        if (px != py) {
            parents[px] += parents[py];
            parents[py] = px;
        }     
    }

    bool same(int x, int y) { //x,yが同じグループにいるか判定
        return find(x) == find(y);
    }

    int size(int x) { //xと同じグループのメンバーの個数
        return -parents[find(x)];
    }
    
    vector<int> root() {//ufの根を列挙
        vector<int> res;
        for (int i = 0; i < N; i ++) {
            if (parents[i] < 0) res.push_back(i);
        }
        return res;
    }

    int group_count() { //ufのグループの数を数える
        int cnt = 0;
        for (int i = 0; i < N; i ++) {
            if (parents[i] < 0) cnt ++;
        }
        return cnt;
    }
};

int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);

    int N; 
    ll A,B; cin >> N >> B >> A;
    vector<ll> X(N);
    rep(i,N) cin >> X[i];
    
    UnionFind uf(N);
    rep(i,N) {
        int l = lower_bound(X.begin(),X.end(),X[i] - A) - X.begin();
        if (l < N && X[l] <= X[i] - B) uf.unite(i,l);
        int r = lower_bound(X.begin(),X.end(),X[i] + B) - X.begin();
        if (r < N && X[r] <= X[i] + A) uf.unite(i,r);
    }
    rep(i,N - 1) {
        int l = lower_bound(X.begin(),X.end(),X[i + 1] - A) - X.begin();
        if (l < N && X[l] <= X[i] - B) uf.unite(i,i + 1);
        int r = lower_bound(X.begin(),X.end(),X[i + 1] + B) - X.begin();
        if (r < N && X[r] <= X[i] + A) uf.unite(i,i + 1);
    }
    rep(i,N) cout << uf.size(i) << '\n';
    return 0;
}