/* Code for problem C by cookiedoth Generated 14 Aug 2020 at 04.04 PM ▅███████ ]▄▄▄▄▄▄▄ █████████▅▄▃ Il████████████████] ◥⊙▲⊙▲⊙▲⊙▲⊙▲⊙▲⊙◤ o_O -_- ~_^ */ #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #define ll long long #define ld long double #define null NULL #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define debug(a) cerr << #a << " = " << a << endl #define forn(i, n) for (int i = 0; i < n; ++i) using namespace std; template int chkmax(T &a, T b) { if (b > a) { a = b; return 1; } return 0; } template int chkmin(T &a, T b) { if (b < a) { a = b; return 1; } return 0; } template void output(iterator begin, iterator end, ostream& out = cerr) { while (begin != end) { out << (*begin) << " "; begin++; } out << endl; } template void output(T x, ostream& out = cerr) { output(x.begin(), x.end(), out); } void fast_io() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); } const int mx = 2e5 + 228; int n, a, b, x[mx], par[mx], sz[mx]; set not_joined; int get_root(int v) { return (par[v] == v ? v : par[v] = get_root(par[v])); } void join(int u, int v) { u = get_root(u); v = get_root(v); if (u != v) { par[u] = v; sz[v] += sz[u]; } } void read() { cin >> n >> a >> b; for (int i = 0; i < n; ++i) { cin >> x[i]; } iota(par, par + n, 0); fill(sz, sz + n, 1); for (int i = 0; i < n - 1; ++i) { not_joined.insert(i); } } void process() { for (int i = 0; i < n; ++i) { int L = lower_bound(x, x + n, x[i] - b) - x; int R = upper_bound(x, x + n, x[i] - a) - x; if (R > L) { join(i, L); while (true) { auto it = not_joined.lower_bound(L); if (it == not_joined.end() || (*it) >= R - 1) { break; } else { join(*it, (*it) + 1); not_joined.erase(it); } } } } } void print_ans() { for (int i = 0; i < n; ++i) { cout << sz[get_root(i)] << '\n'; } } signed main() { fast_io(); read(); process(); print_ans(); }