#include #include #include #include //#include #include #include #include #include #include //#include #include #include #include //#include #include #include //#include #include #include #include #include const int dx[] = {1, 0, -1, 0}; const int dy[] = {0, 1, 0, -1}; using namespace std; typedef long long ll; typedef vector vi; typedef vector vll; typedef pair pii; const int MAXN = 505; const ll INF = 1ll<<55; int A[MAXN]; ll K[MAXN]; int N; ll M; ll dp[MAXN][MAXN*MAXN]; int main() { cin.tie(0); ios::sync_with_stdio(false); cin >> N >> M; ll sum = 0; for (int i = 0; i < N; i++) cin >> A[i]; for (int i = 0; i < N; i++) { cin >> K[i]; sum += A[i]*K[i]; } if (sum < M) { cout << -1 << endl; return 0; } for (int i = 0; i < N; i++) for (int j = 0; j < MAXN*MAXN; j++) dp[i][j] = INF; dp[0][0] = 0; for (int i = 0; i < N; i++) for (int j = 0; j < MAXN*MAXN; j++) { if (i > 0) dp[i][j] = min(dp[i][j], dp[i-1][j]); if (A[i] <= j) dp[i][j] = min(dp[i][j], dp[i][j-A[i]] + 1); } ll ans = 0; ll T = sum-M; if (T > MAXN*MAXN) { ll cnt = T-MAXN*MAXN; ans += cnt/A[N-1]+1; T -= ans*A[N-1]; } ans += dp[N-1][T]; if (ans >= INF) ans = -1; cout << ans << endl; return 0; }