#include using namespace std; typedef long long ll; #define rep(i, n) for(ll i = 0, i##_len = (n); i < i##_len; i++) #define reps(i, s, n) for(ll i = (s), i##_len = (n); i < i##_len; i++) #define rrep(i, n) for(ll i = (n) - 1; i >= 0; i--) #define rreps(i, e, n) for(ll i = (n) - 1; i >= (e); i--) #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() #define sz(x) ((ll)(x).size()) #define len(x) ((ll)(x).length()) #define endl "\n" template void chmax(T &a, const T b){ a = max(a, b); } template void chmin(T &a, const T b){ a = min(a, b); } template struct LowestCommonAncestor { private: const int LOG; vector dep; const vector> &g; vector> table; void dfs(int idx, int par, int d) { table[0][idx] = par; dep[idx] = d; for(auto &to : g[idx]) { if(to != par) dfs(to, idx, d + 1); } } public: LowestCommonAncestor(const vector> &g, int root) : g(g), dep(g.size()), LOG(32 - __builtin_clz(g.size())) { table.assign(LOG, vector(g.size(), -1)); dfs(root, -1, 0); for(int k = 0; k + 1 < LOG; k++) { for(int i = 0; i < table[k].size(); i++) { if(table[k][i] == -1) table[k + 1][i] = -1; else table[k + 1][i] = table[k][table[k][i]]; } } } int query(int u, int v) { if(dep[u] > dep[v]) swap(u, v); for(int i = LOG - 1; i >= 0; i--) { if(((dep[v] - dep[u]) >> i) & 1) v = table[i][v]; } if(u == v) return u; for(int i = LOG - 1; i >= 0; i--) { if(table[i][u] != table[i][v]) { u = table[i][u]; v = table[i][v]; } } return table[0][u]; } }; ll n; vector> g; vector u, dist; void dfs(ll v, ll p = -1) { for(auto &x : g[v]) { if (x == p) continue; dist[x] = dist[v] + u[x]; dfs(x, v); } } int main() { cin.tie(0); ios::sync_with_stdio(false); // ifstream in("input.txt"); // cin.rdbuf(in.rdbuf()); cin >> n; g.resize(n); rep(i, n - 1) { ll a, b; cin >> a >> b; g[a].push_back(b); g[b].push_back(a); } u.resize(n); rep(i, n) cin >> u[i]; dist.resize(n); dist[0] = u[0]; dfs(0); LowestCommonAncestor lca(g, 0); ll m; cin >> m; ll ans = 0; rep(i, m) { ll a, b, c; cin >> a >> b >> c; ll p = lca.query(a, b); ll d = dist[a] + dist[b] - 2 * dist[p] + u[p]; ans += d * c; } cout << ans << endl; return 0; }