#include template inline bool chmin(T&a, T b){if(a > b){a = b; return true;}else{return false;}} template inline bool chmax(T&a, T b){if(a < b){a = b; return true;}else{return false;}} #define ll long long #define double long double #define rep(i,n) for(int i=0;i<(n);i++) #define REP(i,n) for(int i=1;i<=(n);i++) #define mod (ll)(1e9+7) #define inf (ll)(3e18+7) #define pi (double) acos(-1.0) #define P pair #define PiP pair> #define all(x) x.begin(),x.end() #define rall(x) x.rbegin(),x.rend() using namespace std; //update(x, y) := x番目の値をyに //query(x, y) := [x, y)の最小値を返す struct Segtree { const int INF = 0; int n; vector dat; Segtree(int n_) : n(), dat(n_ * 4, INF) { int x = 1; while (n_ > x) { x *= 2; } n = x; } void update(int i, int x) { i += n - 1; dat[i] = x; while (i > 0) { i = (i - 1) / 2; dat[i] = max(dat[i * 2 + 1], dat[i * 2 + 2]); } } int query(int a, int b) { return query_sub(a, b, 0, 0, n); } int query_sub(int a, int b, int k, int l, int r) { if (r <= a || b <= l) { return INF; } else if (a <= l && r <= b) { return dat[k]; } else { int vl = query_sub(a, b, k * 2 + 1, l, (l + r) / 2); int vr = query_sub(a, b, k * 2 + 2, (l + r) / 2, r); return max(vl, vr); } } }; int n; vector a(100010); int solve1(){ Segtree seg1(n+1), seg2(n+1); vector v1(n), v2(n); rep(i, n){ v1[i] = seg1.query(0, a[i]) + 1; int bf = seg1.query(a[i], a[i]+1); seg1.update(a[i], max(v1[i], bf)); } for(int i = n-1; i >= 0; i--){ v2[i] = seg2.query(0, a[i]) + 1; int bf = seg2.query(a[i], a[i]+1); seg2.update(a[i], max(v2[i], bf)); } int ans = 0; rep(i, n)chmax(ans, min(v1[i], v2[i])-1); return ans; } int solve2(){ Segtree seg1(n+1), seg2(n+1); vector v1(n), v2(n); rep(i, n){ v1[i] = seg1.query(a[i]+1, n+1) + 1; int bf = seg1.query(a[i], a[i]+1); seg1.update(a[i], max(v1[i], bf)); } for(int i = n-1; i >= 0; i--){ v2[i] = seg2.query(a[i]+1, n+1) + 1; int bf = seg2.query(a[i], a[i]+1); seg2.update(a[i], max(v2[i], bf)); } int ans = 0; rep(i, n)chmax(ans, min(v1[i], v2[i])-1); return ans; } int main(){ cin >> n; map mp1, mp2; rep(i, n){ cin >> a[i]; mp1[a[i]]++; } int now = 1; for(auto x : mp1){ mp2[x.first] = now; now++; } rep(i, n)a[i] = mp2[a[i]]; cout << max(solve1(), solve2()) << endl; }