//(A + B)(A - B) = N -> よく分からん
//Bを固定してAを動かす気持ちと関連して、A = B + n (n > 0)とおきたい.
//2Bn + n^2 = N
//・2B + 1 = N, n = 1 ⇔ B % 2 == 1 and B >= 3
//・4B + 4 = N, n = 2 ⇔ B % 4 == 0 and B >= 8
//で、n >= 3についてはこの2つに帰着できて、これが存在条件.
#include <iostream>
#include <string>
using namespace std;

int main() {
	string s;
	cin >> s;
	
	if (s.length() == 1) {
		if (s[0] == '3' || s[0] == '5' || s[0] == '7' || s[0] == '8' || s[0] == '9') {
			cout << 1 << endl;
		}
		else {
			cout << -1 << endl;
		}
	}
	else {
		int mod4 = 0;
		for (int i = 0; i < s.length(); i++) {
			mod4 *= 10;
			mod4 += s[i] - '0';
			mod4 %= 4;
		}
		if (mod4 != 2) { cout << 1 << endl; }
		else { cout << -1 << endl; }
	}
	return 0;
}