#include <bits/stdc++.h> using namespace std; typedef signed long long ll; #undef _P #define _P(...) (void)printf(__VA_ARGS__) #define FOR(x,to) for(x=0;x<(to);x++) #define FORR(x,arr) for(auto& x:arr) #define ITR(x,c) for(__typeof(c.begin()) x=c.begin();x!=c.end();x++) #define ALL(a) (a.begin()),(a.end()) #define ZERO(a) memset(a,0,sizeof(a)) #define MINUS(a) memset(a,0xff,sizeof(a)) //------------------------------------------------------- int N; int A[101010]; int B[101010]; ll D[202020]; ll E[202020]; template<class V, int ME> class BIT { public: V bit[1<<ME]; V operator()(int e) {if(e<0) return 0;V s=0;e++;while(e) s+=bit[e-1],e-=e&-e; return s;} void add(int e,V v) { e++; while(e<=1<<ME) bit[e-1]+=v,e+=e&-e;} }; BIT<int,20> bt; map<int,set<int>> C; void solve() { int i,j,k,l,r,x,y; string s; cin>>N; FOR(i,N) cin>>A[i]; FOR(i,N) cin>>B[i]; if(A[0]!=B[0]) return _P("-1\n"); FOR(i,N-1) { C[A[i]^A[i+1]].insert(i); } ll sum=0; FOR(i,N-1) { x=B[i]^B[i+1]; if(C.count(x)==0 || C[x].size()==0) return _P("-1\n"); y=*C[x].begin(); C[x].erase(C[x].begin()); sum+=bt(N+1)-bt(y); bt.add(y,1); } cout<<sum<<endl; } int main(int argc,char** argv){ string s;int i; if(argc==1) ios::sync_with_stdio(false), cin.tie(0); FOR(i,argc-1) s+=argv[i+1],s+='\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin); cout.tie(0); solve(); return 0; }