#include #define rep(i,N) for(ll (i)=0;(i)<(N);(i)++) #define chmax(x,y) x=max(x,y) #define chmin(x,y) x=min(x,y) using namespace std; typedef long long ll; typedef pair P; const int mod = 1000000007; const int INF = 1001001001; struct mint { ll x; // typedef long long ll; mint(ll x=0):x((x%mod+mod)%mod){} mint operator-() const { return mint(-x);} mint& operator+=(const mint a) { if ((x += a.x) >= mod) x -= mod; return *this; } mint& operator-=(const mint a) { if ((x += mod-a.x) >= mod) x -= mod; return *this; } mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;} mint operator+(const mint a) const { return mint(*this) += a;} mint operator-(const mint a) const { return mint(*this) -= a;} mint operator*(const mint a) const { return mint(*this) *= a;} mint pow(ll t) const { if (!t) return 1; mint a = pow(t>>1); a *= a; if (t&1) a *= *this; return a; } // for prime mod mint inv() const { return pow(mod-2);} mint& operator/=(const mint a) { return *this *= a.inv();} mint operator/(const mint a) const { return mint(*this) /= a;} }; istream& operator>>(istream& is, const mint& a) { return is >> a.x;} ostream& operator<<(ostream& os, const mint& a) { return os << a.x;} mint dp[1000001][3]; int main() { int n; cin >> n; dp[0][1] = 1; rep(i, n) { dp[i + 1][0] = dp[i][2] + dp[i][1]; dp[i + 1][1] = dp[i][0]; dp[i + 1][2] = dp[i][1]; } mint ans = dp[n - 1][0] + dp[n - 1][1] + dp[n - 1][2]; cout << ans << endl; }