# coding:utf-8

import sys
# from itertools import product

#
#
#ume = [0, 0, 1, 3, 6, 11, 21, 42, 85, 171, 342, 683, 1365, 2730, 5461, 10923, 21846, 43691, 87381, 174762, 349525,
#	   699051, 1398102, 2796203, 5592405, 10000001]

ume_i = [0,22, 23, 24, 24, 24, 25, 25, 25, 25, 25]
ume_j = [0,1805703, 3611383, 1222795, 7222771, 13222757, 2445581, 8445561, 14445575, 20445563, 26445559]


#def popcount(x):
#	return bin(x).count("1")


def popcount(n):
	n = (n & 0x5555555555555555) + ((n & 0xAAAAAAAAAAAAAAAA) >> 1)
	n = (n & 0x3333333333333333) + ((n & 0xCCCCCCCCCCCCCCCC) >> 2)
	n = (n & 0x0F0F0F0F0F0F0F0F) + ((n & 0xF0F0F0F0F0F0F0F0) >> 4)
	n = (n & 0x00FF00FF00FF00FF) + ((n & 0xFF00FF00FF00FF00) >> 8)
	n = (n & 0x0000FFFF0000FFFF) + ((n & 0xFFFF0000FFFF0000) >> 16)
	n = (n & 0x00000000FFFFFFFF) + ((n & 0xFFFFFFFF00000000) >> 32) 
	return n

# if N in ume:
#     print(ume.index(N))
#     sys.exit()
# else:
def solve():
	N = int(input())
	count = 0
	
	# 100000毎にume
#	ume_i = []
#	ume_j = []
#	c = 1000000
	
	p = int(N/1000000)

	start_i = ume_i[p]
	start_j = ume_j[p]
	if p!=0:
		count = p*1000000-1
	
	x = 0
	for i in range(start_i,26):
		for j in range(start_j,10000000000000):
			a = bin(j)[2:]
			if len(a)>i:
				break
			if popcount(j)%3==0 and popcount(j)>=3 and a[-1]=='1':
				count += 1
#				====
#				if count == c:
#					ume_i.append(i)
#					ume_j.append(j)
#					c += 1000000
#				====
				if count==N:
					
					a = '0'*(i-len(a))+a
					n = a.replace('0', '3').replace('1', '5')
					x = ''.join(n)
					x = int(x)
					print(x)
					sys.exit()

solve()