#include "bits/stdc++.h" using namespace std; const int MAX = 700000; const int MOD = 1000000007; long long fac[MAX], finv[MAX], inv[MAX]; // テーブルを作る前処理 void COMinit() { fac[0] = fac[1] = 1; finv[0] = finv[1] = 1; inv[1] = 1; for (int i = 2; i < MAX; i++) { fac[i] = fac[i - 1] * i % MOD; inv[i] = MOD - inv[MOD % i] * (MOD / i) % MOD; finv[i] = finv[i - 1] * inv[i] % MOD; } } // 二項係数計算 long long COM(int n, int k) { if (n < k) return 0; if (n < 0 || k < 0) return 0; return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD; } /*第二引数で第一引数を割ったときの切り上げの計算*/ long long int maxtime(long long int x, long long int y) { return(x + y - 1) / y; } /*最大公約数*/ long long int lcm(long long int number1, long long int number2) { long long int m = number1; long long int n = number2; if (number2 > number1) { m = number2; n = number1; } long long int s = -1; while (s != 0) { s = m % n; m = n; n = s; } return m; } /*最大公倍数*/ long long int gcd(long long int number1, long long int number2) { long long int m = number1; long long int n = number2; return m / lcm(m, n) * n; } /*逆元計算*/ long long int modinv(long long a, long long m) { long long int b = m, u = 1, v = 0; while (b) { long long int t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v); } u %= m; if (u < 0) u += m; return u; } // index が条件を満たすかどうか vectormeguru; bool isOK(int index, int key) { if (meguru[index] <= key) return true; else return false; } // 汎用的な二分探索のテンプレ int binary_search(int key) { int left = -1; //「index = 0」が条件を満たすこともあるので、初期値は -1 int right = (int)meguru.size(); // 「index = a.size()-1」が条件を満たさないこともあるので、初期値は a.size() /* どんな二分探索でもここの書き方を変えずにできる! */ while (right - left > 1) { int mid = left + (right - left) / 2; if (isOK(mid, key)) left = mid; else right = mid; } /* left は条件を満たす最大の値、right は条件を満たさない最小の値になっている */ return left; } long long modpow(long long a, long long n, long long mod) { long long res = 1; while (n > 0) { if (n & 1) res = res * a % mod; a = a * a % mod; n >>= 1; } return res; } double PI = 3.141592653589793238; int main() { int n; cin >> n; int dp[1030] = {}; for (int i = 1; i <= n; i++) { int a = i; while (a > 0) { if (a % 2 == 1) { dp[i]++; } a = a / 2; } //cout << dp[i] << endl; } queueq; q.push(1); int susum[1030] = {}; susum[1] = 1; while (q.size()) { int now = q.front(); //cout << now << endl; q.pop(); int b = dp[now]; if (now == n) { cout << susum[now]; return 0; } if (now - b > 0 && now - b <= n) { if (susum[now - b] == 0) { q.push(now - b); susum[now - b] = susum[now] + 1; } } if (now + b > 0 && now + b <= n) { if (susum[now + b] == 0) { q.push(now + b); susum[now + b] = susum[now] + 1; } } } cout << -1; }