#pragma GCC optimize("O3") #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; using ll = long long; using P = pair; using T = tuple; template inline T chmax(T &a, const T b) {return a = (a < b) ? b : a;} template inline T chmin(T &a, const T b) {return a = (a > b) ? b : a;} constexpr int MOD = 1e9 + 7; constexpr int inf = 1e9; constexpr long long INF = 1e18; #define all(a) (a).begin(), (a).end() int dx[] = {1, 0, -1, 0}; int dy[] = {0, 1, 0, -1}; ll modpow(ll a, ll b){ if(b == 0) return 1; else if(b % 2 == 0){ ll d = modpow(a, b / 2) % MOD; return (d * d) % MOD; } else{ return (a * modpow(a, b - 1)) % MOD; } } int main(){ cin.tie(0); ios::sync_with_stdio(false); int h, w; cin>>h>>w; vector> a(h, vector(w)); ll allsum = 1; for(int i=0; i>a[i][j]; allsum *= a[i][j]; allsum %= MOD; } } vector hsum(h, 1), wsum(w, 1); for(int i=0; i>q; while(q--){ int r, c; cin>>r>>c; r--, c--; ll ans = allsum; ans *= modpow(hsum[r], MOD - 2); ans %= MOD; ans *= modpow(wsum[c], MOD - 2); ans %= MOD; ans *= a[r][c]; cout << ans % MOD << endl; } return 0; }