#include //#include //#pragma GCC optimize("Ofast") using namespace std; #define reps(i,s,n) for(int i = s; i < n; i++) #define rep(i,n) reps(i,0,n) #define Rreps(i,n,e) for(int i = n - 1; i >= e; --i) #define Rrep(i,n) Rreps(i,n,0) #define ALL(a) a.begin(), a.end() #define fi first #define se second using ll = long long; using vec = vector; using mat = vector; ll N,M,H,W,Q,K,A,B; string S; typedef pair P; const ll INF = (1LL<<58); template class modint{ public: ll x; constexpr modint(){x = 0;} constexpr modint(ll _x) : x((_x < 0 ? ((_x += (LLONG_MAX / mod) * mod) < 0 ? _x + (LLONG_MAX / mod) * mod : _x) : _x)%mod){} constexpr void set_raw(ll _x){ //_x in [0, mod) x = _x; } constexpr modint operator-(){ return x == 0 ? 0 : mod - x; } constexpr modint& operator+=(const modint& a){ if((x += a.x) >= mod) x -= mod; return *this; } constexpr modint operator+(const modint& a) const{ return modint(*this) += a; } constexpr modint& operator-=(const modint& a){ if((x -= a.x) < 0) x += mod; return *this; } constexpr modint operator-(const modint& a) const{ return modint(*this) -= a; } constexpr modint& operator*=(const modint& a){ (x *= a.x)%=mod; return *this; } constexpr modint operator*(const modint& a) const{ return modint(*this) *= a; } constexpr modint pow(unsigned long long pw) const{ modint res(1), comp(*this); while(pw){ if(pw&1) res *= comp; comp *= comp; pw >>= 1; } return res; } //以下、modが素数のときのみ constexpr modint inv() const{ return modint(*this).pow(mod - 2); } constexpr modint& operator/=(const modint &a){ (x *= a.inv().x)%=mod; return *this; } constexpr modint operator/(const modint &a) const{ return modint(*this) /= a; } }; #define mod2 1000000007 using mint = modint; ostream& operator<<(ostream& os, const mint& a){ os << a.x; return os; } using vm = vector; int main() { cin>>N>>K; vector a(N); rep(i, N) cin>>a[i]; const int max_sum = K * N; vector dp(N + 1, vm(max_sum + 1, 0)); dp[0][0] = 1; struct query{int j, k; mint a; query(int _j, int _k, mint _a) : j(_j), k(_k), a(_a){}}; rep(i, N){ queue que; rep(j, N + 1){ rep(k, max_sum + 1){ if(dp[j][k].x != 0) que.emplace(j + 1, min(max_sum, k + a[i]), dp[j][k]); } } while(!que.empty()){ query q = que.front(); que.pop(); dp[q.j][q.k] += q.a; } } mint res(0); reps(j, 1, N + 1){ rep(k, max_sum + 1){ if(j * K <= k) res += dp[j][k]; } } cout<