#include <bits/stdc++.h>
#define rep(i, n) for (int i = 0; i < (n); ++i)
using namespace std;
using ll = long long;

const int mod = 1000000007;
struct mint {
    ll x;  // typedef long long ll;
    mint(ll x = 0) : x((x % mod + mod) % mod) {}
    mint operator-() const { return mint(-x); }
    mint& operator+=(const mint a) {
        if ((x += a.x) >= mod) x -= mod;
        return *this;
    }
    mint& operator-=(const mint a) {
        if ((x += mod - a.x) >= mod) x -= mod;
        return *this;
    }
    mint& operator*=(const mint a) {
        (x *= a.x) %= mod;
        return *this;
    }
    mint operator+(const mint a) const { return mint(*this) += a; }
    mint operator-(const mint a) const { return mint(*this) -= a; }
    mint operator*(const mint a) const { return mint(*this) *= a; }
    mint pow(ll t) const {
        if (!t) return 1;
        mint a = pow(t >> 1);
        a *= a;
        if (t & 1) a *= *this;
        return a;
    }

    // for prime mod
    mint inv() const { return pow(mod - 2); }
    mint& operator/=(const mint a) { return *this *= a.inv(); }
    mint operator/(const mint a) const { return mint(*this) /= a; }
};
istream& operator>>(istream& is, mint& a) { return is >> a.x; }
ostream& operator<<(ostream& os, const mint& a) { return os << a.x; }

// combination mod prime
// https://www.youtube.com/watch?v=8uowVvQ_-Mo&feature=youtu.be&t=1619
struct combination {
    vector<mint> fact, ifact;
    combination(int n) : fact(n + 1), ifact(n + 1) {
        assert(n < mod);
        fact[0] = 1;
        for (int i = 1; i <= n; ++i) fact[i] = fact[i - 1] * i;
        ifact[n] = fact[n].inv();
        for (int i = n; i >= 1; --i) ifact[i - 1] = ifact[i] * i;
    }
    mint operator()(int n, int k) {
        if (k < 0 || k > n) return 0;
        return fact[n] * ifact[k] * ifact[n - k];
    }
};

int main() {
    ll N, K;
    cin >> N >> K;

    vector<ll> a(N);
    rep(i, N) {
        cin >> a[i];
        a[i] -= K;
    }
    sort(a.rbegin(), a.rend());
    rep(i, N) {
        ll target = i + 1;
        ll needNum = K * target;
    }
    int maxM = int(1e4) + 5;
    mint dp[N + 1][maxM] = {};
    dp[0][0] = 1;
    rep(i, N) rep(j, maxM) {
        dp[i + 1][j] += dp[i][j];
        if (dp[i][j].x) {
            if (j + a[i] >= 0) {
                dp[i + 1][j + a[i]] += dp[i][j];
            }
        }
    }
    mint ans = -1;
    rep(i, maxM) {
        ans += dp[N][i];
    }
    cout << ans << endl;

    return 0;
}