#include using namespace std; #define rep(i,n) for(ll i=0;i=0;i--) #define perl(i,r,l) for(ll i=r-1;i>=l;i--) #define fi first #define se second #define pb push_back #define ins insert #define pqueue(x) priority_queue,greater> #define all(x) (x).begin(),(x).end() #define CST(x) cout<; using vvl=vector>; using pl=pair; using vpl=vector; using vvpl=vector; const ll MOD=1000000007; const ll MOD9=998244353; const int inf=1e9+10; const ll INF=4e18; const ll dy[8]={1,0,-1,0,1,1,-1,-1}; const ll dx[8]={0,-1,0,1,1,-1,1,-1}; template inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; } template inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; } const int mod = MOD9; const int max_n = 200005; struct mint { ll x; // typedef long long ll; mint(ll x=0):x((x%mod+mod)%mod){} mint operator-() const { return mint(-x);} mint& operator+=(const mint a) { if ((x += a.x) >= mod) x -= mod; return *this; } mint& operator-=(const mint a) { if ((x += mod-a.x) >= mod) x -= mod; return *this; } mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;} mint operator+(const mint a) const { return mint(*this) += a;} mint operator-(const mint a) const { return mint(*this) -= a;} mint operator*(const mint a) const { return mint(*this) *= a;} mint pow(ll t) const { if (!t) return 1; mint a = pow(t>>1); a *= a; if (t&1) a *= *this; return a; } bool operator==(const mint &p) const { return x == p.x; } bool operator!=(const mint &p) const { return x != p.x; } // for prime mod mint inv() const { return pow(mod-2);} mint& operator/=(const mint a) { return *this *= a.inv();} mint operator/(const mint a) const { return mint(*this) /= a;} }; istream& operator>>(istream& is, mint& a) { return is >> a.x;} ostream& operator<<(ostream& os, const mint& a) { return os << a.x;} int main(){ mint ans=0; ll n;cin >> n; vl a(n);rep(i,n)cin >> a[i]; rep(i,n){ if(abs(a[i])!=2)continue; vl lp,lm,rp,rm; ll cnt=1; per(j,i){ if(abs(a[j])!=1)break; cnt*=a[j]; if(cnt==1)lp.push_back(j); else lm.push_back(j); } cnt=1; repl(j,i+1,n){ if(abs(a[j])!=1)break; cnt*=a[j]; if(cnt==1)rp.push_back(j); else rm.push_back(j); } if(a[i]==-2){ //lm.push_back(i);rm.push_back(i); lp.push_back(i);rp.push_back(i); mint ra=0,rb=0,rc=0,rd=0; for(auto z:lp){ ra+=mint(2).pow(max(0LL,z-1)); } for(auto z:rp){ rb+=mint(2).pow(max(0LL,n-z-2)); } for(auto z:lm){ rc+=mint(2).pow(max(0LL,z-1)); } for(auto z:rm){ rd+=mint(2).pow(max(0LL,n-z-2)); } ans+=ra*rb+rc*rd;//-mint(2).pow(n-2); //cout << ans <