#include <bits/stdc++.h>
using namespace std;
typedef long long ll;

int main() {
    int A, B;
    cin >> A >> B;
    int f1 = (2 * 6 * B) % 360;
    int f2 = (2 * 30 * A + B) % 360;
    if (f1 > f2) {
        cout << (360 - (f1 - f2)) * 60 / 11 << "\n";
    } else {
        cout << (f2 - f1) * 60 / 11 << "\n";
    }
    
    return 0;
}