#include <bits/stdc++.h>
using namespace std;
typedef long long ll;

int main() {
    int A, B;
    cin >> A >> B;
    A %= 12;
    double t1 = (6 * B) % 360;
    double t2 = (30 * A) % 360 + (double)B / 2.0;
    //cout << t1 << " " << t2 << "\n";
    int f1 = 2 * 6 * B;
    int f2 = 2 * 30 * A + B;
    if (t1 > t2) {
        cout << (360 - (f1 - f2)) * 60 / 11 << "\n";
    } else {
        cout << (f2 - f1) * 60 / 11 << "\n";
    }
    // cout << (360 - (f1 - f2)) * 60 / 11 << "\n";
    // cout << (f2 - f1) * 60 / 11 << "\n";
    return 0;
}