/** * @FileName a.cpp * @Author kanpurin * @Created 2020.10.07 18:39:23 **/ #include "bits/stdc++.h" using namespace std; typedef long long ll; template< int MOD > struct mint { public: long long x; mint(long long x = 0) :x((x%MOD+MOD)%MOD) {} mint(std::string &s) { long long z = 0; for (int i = 0; i < s.size(); i++) { z *= 10; z += s[i] - '0'; z %= MOD; } this->x = z; } mint& operator+=(const mint &a) { if ((x += a.x) >= MOD) x -= MOD; return *this; } mint& operator-=(const mint &a) { if ((x += MOD - a.x) >= MOD) x -= MOD; return *this; } mint& operator*=(const mint &a) { (x *= a.x) %= MOD; return *this; } mint& operator/=(const mint &a) { long long n = MOD - 2; mint u = 1, b = a; while (n > 0) { if (n & 1) { u *= b; } b *= b; n >>= 1; } return *this *= u; } mint operator+(const mint &a) const { mint res(*this); return res += a; } mint operator-() const {return mint() -= *this; } mint operator-(const mint &a) const { mint res(*this); return res -= a; } mint operator*(const mint &a) const { mint res(*this); return res *= a; } mint operator/(const mint &a) const { mint res(*this); return res /= a; } friend std::ostream& operator<<(std::ostream &os, const mint &n) { return os << n.x; } friend std::istream &operator>>(std::istream &is, mint &n) { long long x; is >> x; n = mint(x); return is; } bool operator==(const mint &a) const { return this->x == a.x; } mint pow(long long k) const { mint ret = 1; mint p = this->x; while (k > 0) { if (k & 1) { ret *= p; } p *= p; k >>= 1; } return ret; } }; constexpr int MOD = 1e9 + 7; template struct Combination { private: int N; public: vector< T > FACT, IFACT; Combination(int n) : N(n) { FACT.resize(n + 1); IFACT.resize(n + 1); FACT[0] = 1; IFACT[0] = 1; for (int i = 1; i <= n; i++) { FACT[i] = FACT[i - 1] * i; IFACT[i] = T(1) / FACT[i]; } } T comb(int n, int r) { if (n < 0 || r < 0 || r > n) return 0; if (r > n / 2) r = n - r; return FACT[n] * IFACT[n - r] * IFACT[r]; } }; int main() { int n,r,g,b;cin >> n >> r >> g >> b; int S = r + g + b; Combination> cb(3001); mint ans = 0; for (int K = -n + 2 * S - 1; 2 * K <= S && max({r,g,b}) + K <= S; K++) { mint sum = 0; for (int k = K - min(g,b); k <= K; k++) { sum += cb.comb(S-2*K,r-k) * cb.comb(K,k) * cb.comb(g+b-2*K+2*k,g-K+k); } ans += sum * cb.comb(S-K,K)*cb.comb(n-S+1,S-K) * mint(2).pow(K); } cout << ans << endl; return 0; }