#include #include #include #include #include #include #include #include #include static const int MOD = 1000000007; using ll = long long; using u32 = unsigned; using u64 = unsigned long long; using namespace std; template constexpr T INF = ::numeric_limits::max()/32*15+208; template struct modint { u32 val; public: static modint raw(int v) { modint x; x.val = v; return x; } modint() : val(0) {} template modint(T v) { ll x = (ll)(v%(ll)(M)); if (x < 0) x += M; val = u32(x); } modint(bool v) { val = ((unsigned int)(v) % M); } modint& operator++() { val++; if (val == M) val = 0; return *this; } modint& operator--() { if (val == 0) val = M; val--; return *this; } modint operator++(int) { modint result = *this; ++*this; return result; } modint operator--(int) { modint result = *this; --*this; return result; } modint& operator+=(const modint& b) { val += b.val; if (val >= M) val -= M; return *this; } modint& operator-=(const modint& b) { val -= b.val; if (val >= M) val += M; return *this; } modint& operator*=(const modint& b) { u64 z = val; z *= b.val; val = (u32)(z % M); return *this; } modint& operator/=(const modint& b) { return *this = *this * b.inv(); } modint operator+() const { return *this; } modint operator-() const { return modint() - *this; } modint pow(long long n) const { modint x = *this, r = 1; while (n) { if (n & 1) r *= x; x *= x; n >>= 1; } return r; } modint inv() const { return pow(M-2); } friend modint operator+(const modint& a, const modint& b) { return modint(a) += b; } friend modint operator-(const modint& a, const modint& b) { return modint(a) -= b; } friend modint operator*(const modint& a, const modint& b) { return modint(a) *= b; } friend modint operator/(const modint& a, const modint& b) { return modint(a) /= b; } friend bool operator==(const modint& a, const modint& b) { return a.val == b.val; } friend bool operator!=(const modint& a, const modint& b) { return a.val != b.val; } }; using mint = modint; void solve(){ ll n; int a, b, c, d, e, f; scanf("%lld %d %d %d %d %d %d", &n, &a, &b, &c, &d, &e, &f); mint p = mint(a)/mint(b), q = mint(c)/mint(d), r = mint(e)/mint(f); printf("%d\n", (1-(p+q).pow(n)-(q+r).pow(n)-(r+p).pow(n) + p.pow(n)*2 + q.pow(n)*2 + r.pow(n)*2).val); } int main() { int t; cin >> t; while(t--){ solve(); } return 0; }