#include <bits/stdc++.h>
using namespace std;
typedef signed long long ll;

#undef _P
#define _P(...) (void)printf(__VA_ARGS__)
#define FOR(x,to) for(x=0;x<(to);x++)
#define FORR(x,arr) for(auto& x:arr)
#define FORR2(x,y,arr) for(auto& [x,y]:arr)
#define ITR(x,c) for(__typeof(c.begin()) x=c.begin();x!=c.end();x++)
#define ALL(a) (a.begin()),(a.end())
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
//-------------------------------------------------------

int N;
ll A[202020],B[202020];

double hoge(double v) {
	double ret=0;
	int i;
	FOR(i,N) ret+=B[i]*abs(v-A[i]);
	return ret;
}

void solve() {
	int i,j,k,l,r,x,y; string s;
	
	cin>>N;
	FOR(i,N) cin>>A[i];
	FOR(i,N) cin>>B[i];
	
	double L=-1<<30,R=1<<30;
	FOR(i,120) {
		double m1=(2*L+R)/3;
		double m2=(2*R+L)/3;
		double v1=hoge(m1);
		double v2=hoge(m2);
		if(v1<=v2) R=m2;
		if(v2<=v1) L=m1;
	}
	_P("%.12lf %lld\n",L,(ll)round(hoge(L)));
}


int main(int argc,char** argv){
	string s;int i;
	if(argc==1) ios::sync_with_stdio(false), cin.tie(0);
	FOR(i,argc-1) s+=argv[i+1],s+='\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);
	cout.tie(0); solve(); return 0;
}