#pragma GCC optimize("O3") #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; using ll = long long; using P = pair; using T = tuple; template inline T chmax(T &a, const T b) {return a = (a < b) ? b : a;} template inline T chmin(T &a, const T b) {return a = (a > b) ? b : a;} constexpr int MOD = 1e9 + 7; constexpr int inf = 1e9; constexpr long long INF = 1e18; #define all(a) (a).begin(), (a).end() int dx[] = {1, 0, -1, 0}; int dy[] = {0, 1, 0, -1}; int n; vector children(200010); ll ans = 0; void dfs1(int cv, int pv, vector> &G){ int sum = 1; for(auto nxt : G[cv]){ int nv, cost; tie(nv, cost) = nxt; if(nv == pv) continue; dfs1(nv, cv, G); sum += children[nv]; } children[cv] = sum; return; } void dfs2(int cv, int pv, vector> &G){ for(auto nxt : G[cv]){ int nv, cost; tie(nv, cost) = nxt; if(nv == pv) continue; ans += children[nv] * (n - children[nv]) * cost; dfs2(nv, cv, G); } return ; } int main(){ cin.tie(0); ios::sync_with_stdio(false); cin>>n; vector> G(n); for(int i=0; i>u>>v>>w; u--, v--; G[u].emplace_back(v, w); G[v].emplace_back(u, w); } dfs1(0, -1, G); dfs2(0, -1, G); cout << ans * 2 << endl; return 0; }