package main import ( "bufio" "fmt" "os" "sort" "strconv" ) var sc = bufio.NewScanner(os.Stdin) var wr = bufio.NewWriter(os.Stdout) func out(x ...interface{}) { fmt.Fprintln(wr, x...) } func getI() int { sc.Scan() i, e := strconv.Atoi(sc.Text()) if e != nil { panic(e) } return i } func getF() float64 { sc.Scan() i, e := strconv.ParseFloat(sc.Text(), 64) if e != nil { panic(e) } return i } func getInts(N int) []int { ret := make([]int, N) for i := 0; i < N; i++ { ret[i] = getI() } return ret } func getS() string { sc.Scan() return sc.Text() } // min, max, asub, absなど基本関数 func max(a, b int) int { if a > b { return a } return b } func min(a, b int) int { if a < b { return a } return b } func asub(a, b int) int { if a > b { return a - b } return b - a } func abs(a int) int { if a >= 0 { return a } return -a } func lowerBound(a []int, x int) int { idx := sort.Search(len(a), func(i int) bool { return a[i] >= x }) return idx } func upperBound(a []int, x int) int { idx := sort.Search(len(a), func(i int) bool { return a[i] > x }) return idx } // NextPermutation generates the next permutation of the // sortable collection x in lexical order. It returns false // if the permutations are exhausted. // // Knuth, Donald (2011), "Section 7.2.1.2: Generating All Permutations", // The Art of Computer Programming, volume 4A. // ※NextPermutationは辞書順で次を返す func NextPermutation(x sort.Interface) bool { n := x.Len() - 1 if n < 1 { return false } j := n - 1 for ; !x.Less(j, j+1); j-- { if j == 0 { return false } } l := n for !x.Less(j, l) { l-- } x.Swap(j, l) for k, l := j+1, n; k < l; { x.Swap(k, l) k++ l-- } return true } func t(a []int) int { ret := 0 for { cnt := 0 for i := 1; i < len(a); i++ { if a[i] < a[i-1] { cnt++ } } if a[0] == K && cnt == 1 { ret++ } if NextPermutation(sort.IntSlice(a)) == false { break } } return ret } var N, K int func main() { defer wr.Flush() sc.Split(bufio.ScanWords) sc.Buffer([]byte{}, 1000000) // this template is new version. // use getI(), getS(), getInts(), getF() N, K = getI(), getI() a := make([]int, N) for i := 0; i < N; i++ { a[i] = i + 1 } out(t(a)) // ans := 0 // if K == N { // out(1) // return // } // if K != 1 { // ans++ // } // out(ans) // if N-1 > 1 { // ans += N - K // } // out(ans) t([]int{1, 2, 3, 4, 5, 6, 7}) }