#include using namespace std; #define rep(i, n) for(int(i) = 0; (i) < (n); (i)++) #define FOR(i, m, n) for(int(i) = (m); (i) < (n); (i)++) #define All(v) (v).begin(), (v).end() #define pb push_back #define MP(a, b) make_pair((a), (b)) template vector make_vec(size_t a, T val) { return vector(a, val); } template auto make_vec(size_t a, Ts... ts) { return vector(a, make_vec(ts...)); } using ll = long long; using pii = pair; using pll = pair; using Graph = vector>; template struct edge { int to; T cost; edge(int t, T c) : to(t), cost(c) {} }; template using WGraph = vector>>; const int INF = 1 << 30; const ll LINF = 1LL << 60; const int MOD = 1e9 + 7; // 参考:https://qiita.com/drken/items/1b7e6e459c24a83bb7fd // 1-indexed BIT // add:log(N),sum:log(N),get_k-th:log(N) // https://codeforces.com/contest/1354/problem/D struct BIT { vector dat; BIT(int n) { dat.resize(n + 1); for(int i = 0; i < (int)dat.size(); i++) dat[i] = 0; } // a is 1-indexed void add(int a, ll x) { for(int i = a; i < (int)dat.size(); i += i & -i) dat[i] = dat[i] + x; } // [1,a], a is 1-indexed ll sum(int a) { ll res = 0; for(int i = a; i > 0; i -= i & -i) { res = res + dat[i]; } return res; } // [a,b), a and b are 1-indexed ll sum(int a, int b) { return sum(b - 1) - sum(a - 1); } // k-th number (k is 1-indexed) // lower_bound int get(ll k) { if(k <= 0) return 0; int res = 0; int N = 1; while(N < (int)dat.size()) N *= 2; for(int i = N / 2; i > 0; i /= 2) { if(res + i < (int)dat.size() && dat[res + i] < k) { k = k - dat[res + i]; res = res + i; } } return res + 1; } }; int main() { int N, Q; cin >> N >> Q; vector A(N); rep(i, N) cin >> A[i]; vector> query(Q); BIT bit(N + 1); rep(i, Q) { char c; ll x, y; cin >> c >> x >> y; if(c == 'A') { query[i] = {0, {x, y}}; } else { query[i] = {1, {x, y}}; } } reverse(All(query)); vector res(N); for(auto [q, p] : query) { auto [x, y] = p; if(q == 0) { res[x - 1] += bit.sum(x) * y; } else { bit.add(x, 1); bit.add(y + 1, -1); } } for(int i = 0; i < N; i++) { res[i] += A[i] * bit.sum(i + 1); } for(int i = 0; i < N; i++) { cout << res[i] << (i == N - 1 ? "\n" : " "); } }